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lozanna [386]
3 years ago
13

How much kinetic energy does an 80 kg man have while running at 3 m/s?

Physics
1 answer:
Soloha48 [4]3 years ago
7 0

Hello!

\large\boxed{KE = 360 J}

Use the equation KE = 1/2mv² to solve for the kinetic energy of the man.

We are given the mass and velocity, so plug these values into the equation:

KE = 1/2(80)(3²)

KE = 1/2(720)

KE = 360 J

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Which one of the following types of training involves 10 to 30 minutes of high-intensity exercise?
Goshia [24]

Correct answer choice is:



C. Medium range



Explanation:



Medium range exercises are used to gain extra strength and fitness. Usually, heavyweights are used with less number of repetitions. These sort of exercises are mostly the hardest t do. All you need is to have a high level of motivation and stamina, which can be gained by running or cycling.

5 0
4 years ago
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A 2-m long string is stretched between two supports with a tension that produces a wave speed equal to vw=50.00m/s. What are the
svetoff [14.1K]

Answer

given,

Length of the string, L = 2 m

speed of the wave , v = 50 m/s

string is stretched between two string

For the waves the nodes must be between the strings

the wavelength  is given by

           \lambda = \dfrac{2L}{n}

where n is the number of antinodes; n = 1,2,3,...

the frequency expression is given by

            f = n\dfrac{v}{2L}

now, wavelength calculation

      n = 1

           \lambda_1 = \dfrac{2\times 2}{1}

                    λ₁ = 4 m

      n = 2

           \lambda_2 = \dfrac{2\times 2}{2}

                   λ₂ = 2 m

      n =3

           \lambda_3 = \dfrac{2\times 2}{3}

                    λ₃ = 1.333 m

now, frequency calculation

      n = 1

            f = n\dfrac{v}{2L}

            f_1 =1\times \dfrac{50}{2\times 2}

                    f₁ = 12.5 Hz

      n = 2

            f = n\dfrac{v}{2L}

            f_2 =2\times \dfrac{50}{2\times 2}

                    f₂= 25 Hz

      n = 3

            f = n\dfrac{v}{2L}

            f_3 =3\times \dfrac{50}{2\times 2}

                    f₃ = 37.5 Hz

8 0
3 years ago
10. Find the mass density of a ball with 22.0 g and a radius of 0.875 cm.
Ede4ka [16]

Answer:

Mass (m) = 22.0 g

Radius (r) = 0.875 cm

Density (d) = ?

First find ( volume) ;

v =  \frac{4}{3} \pi \:  {r}^{3}  \\  \\ v =  \frac{4}{3}  \times 3.14 \times ( {0.875)}^{3}  \\  \\ v =  \frac{4}{3}   \times 3.14 \times 0.66992187  \:  {cm}^{3} \\  \\ v = 2.8 \:  {cm}^{3}

Density =  \frac{mass}{volume}  \\  \\ d =  \frac{m}{v}  \\  \\ d =  \frac{22}{2.8}  \\  \\ d = 7.857 \:  \frac{g}{ {cm}^{3} }

I hope I helped you^_^

7 0
3 years ago
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saul85 [17]
ANSWER i believe it's A. wax, which is made up of atoms that share electrons equally
5 0
4 years ago
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Sav [38]

Answer: A. The acceleration of an object is determined by its mass and the net force acting on it.

Explanation:

Newton's second law of motion explains that the acceleration of an object will depend on two vital variables which are the mass of the object and the net force that's acting on it.

It should be noted that the acceleration of the object directly depend on the net force while it depends inversely on the mass. Therefore, when the force that's acting on such object is increased, then the acceleration will increase as well. On the other hand, when there is an increase in mass, there'll be a reduction in the acceleration.

7 0
3 years ago
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