Answer:
7.3 g (NH₄)₃PO₄
Explanation:
The balanced equation for the reaction is:
H₃PO₄ + 3 NH₃ ----> (NH₄)₃PO₄
To find the mass of ammonium phosphate ((NH₄)₃PO₄) produced, you need to (1) convert grams NH₃ to moles NH₃ (via the molar mass from the periodic table), then (2) convert moles NH₃ to moles (NH₄)₃PO₄ (via mole-to-mole ratio from balanced equation), and then (3) convert moles (NH₄)₃PO₄ to grams (NH₄)₃PO₄ (via molar mass from periodic table). Make sure to arrange the ratios/conversions in a way that allows for the cancellation of units. The final answer should have 2 sig figs because the given value (2.5 grams) has 2 sig figs.
Molar Mass (NH₃): 14.01 g/mol + 3(1.008 g/mol)
Molar Mass (NH₃): 17.034 g/mol
Molar Mass ((NH₄)₃PO₄):
3(14.01 g/mol) + 12(1.008 g/mol) + 30.97 g/mol + 4(16.00 g/mol)
Molar Mass ((NH₄)₃PO₄): 149.096 g/mol
2.5 g NH₃ 1 mole NH₃ 1 mole (NH₄)₃PO₄ 149.096 g
--------------- x -------------------- x --------------------------- x --------------------------
17.034 g 3 moles NH₃ 1 mole (NH₄)₃PO₄
= 7.3 g (NH₄)₃PO₄
-1
An ion is an atom which has gained or lost electrons.
Atoms want to have full outer shells of electrons.
Electrons are negative.
Fluorine has 7 electrons in its outer shell. When it gains one to fill its shell it will be made negative.
Thus the charge of a fluorine ion is -1
Answer:
The correct answer is 0.50 mol (NH₄)₃PO₄
Explanation:
The balanced chemical equation between liquid ammonia (NH₃) and H₃PO₄ is the following:
3 NH₃ + H₃PO₄ → (NH₄)₃PO₄
According to the equation, 3 mol of ammonia produce 1 mol of ammonium phosphate. Thus, the stoichiometric ratio is 1 mol (NH₄)₃PO₄/3 NH₃. To calculate the moles of (NH₄)₃PO₄, we multiply the ratio by 1.50 mol NH₃:
1.50 mol NH₃ x 1 mol (NH₄)₃PO₄/3 NH₃ = 0.50 mol (NH₄)₃PO₄
To determine the mass of the sugar molecules given, we need to convert the given value into moles by using the a constant. <span>Avogadro's number
represents the number of units in one mole of any substance. This has the value
of 6.022 x 10^23 units / mole. This number can be used to convert the number of
atoms or molecules into number of moles. Then, by using the molar mass of sugar, we can convert from moles to grams. Molar mass of sugar is 342.3 g/mol. We do as follows:
</span><span>2.50 × 10^25 molecules of sugar ( 1 mol / 6.022x10^23 g ) ( 342.3 g / 1 mol) = 14210.40 grams of sugar present</span>
