Answer:
B = CHCl2 + Cl2 --> CHCl3 + Cl
Explanation:
Free radical halogenation is a chlorination reaction on Alkane hydrocarbons. This involves the splitting of molecules into radicals/ unstable molecules in the presence of sunlight/ U.V light which ensures bonding of the molecules.
Free radical chlorination is divided into 3 steps which are:
The initiation step
The propagation step
The termination step
So in reference to the question, propagation step involves two steps.
The first step is where the molecule in this case the methylene chloride(CH2Cl2) loses a hydrogen atom and then bond with a chlorine atom radical to give a nethylwnw chloride radical and HCl.
The second step involves the reaction of this methylene chloride got in the first step with chlorine molecule to form trichloride methane and a chlorine radical.
You would find in the attachment the 2 step mechanism.
This equation is balanced
<h3>What is the oxidation number of oxygen in H2O?</h3>
Oxygen almost always has an oxidation number of -2, except in peroxides (H 2 O 2) where it is -1 and in compounds with fluorine (OF 2) where it is +2. Hydrogen has an oxidation number of +1 when combined with non-metals, but it has an oxidation number of -1 when combined with metals.
<h3><em>Sure hoep this helps you :)</em></h3>
Molecular orbital energy is the energy associated with each electron in an atom or molecule.
It is expressed in electron volts (eV) and is determined by the electron's position in the atom or molecule. The molecular orbital energy diagram and fill-in the electrons are given here in each case, the number of valence electrons in the species is determined first; this is followed by the valence molecular orbital diagram for each species.
C2+: Molecular Orbital Energy Diagram
1s2 2s2 2p2
σ2s* ← 0 e-
σ2s ← 2 e-
σ2p* ← 0 e-
σ2p ← 0 e-
π2p* ← 0 e-
π2p ← 0 e-
Bond Order: 0
Stability: Unstable
Magnetism: Diamagnetic (no unpaired electrons)
O2-: Molecular Orbital Energy Diagram
1s2 2s2 2p4
σ2s* ← 0 e-
σ2s ← 2 e-
σ2p* ← 0 e-
σ2p ← 2 e-
π2p* ← 0 e-
π2p ← 2 e-
Bond Order: 1
Stability: Stable
Magnetism: Paramagnetic (2 unpaired electrons)
For more questions like Molecular orbital theory click the link below:
brainly.com/question/20436223
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Answer:
The equilibrium constant, K, for the reaction = 0.23
Explanation:
Given that
initial concentrations of phenol(C₆H₅OH) = 0.2 Molar
& concentration of ammonia = 0.12 Molar
At equilibrium the phenoxide ion concentration (C₆H₅O⁻) = 0.05 Molar
C₆H₅OH(aq) + NH₃(aq) ⇄ C₆H₅O⁻(aq) + NH₄⁺(aq)
Initial conc. 0.2 0.12 0 0
Equilibrium (0.2 - 0.05) (0.12 - 0.05) 0.05 0.05
= 0.15 = 0.07
According to law of mass action
![K_{c} =\frac{[C_{6}H_{5}O^{-} ][NH_{4}^{+} ]}{[C_{6}H_{5}OH ][NH_{3} ]}](https://tex.z-dn.net/?f=K_%7Bc%7D%20%3D%5Cfrac%7B%5BC_%7B6%7DH_%7B5%7DO%5E%7B-%7D%20%20%20%5D%5BNH_%7B4%7D%5E%7B%2B%7D%20%20%5D%7D%7B%5BC_%7B6%7DH_%7B5%7DOH%20%20%5D%5BNH_%7B3%7D%20%5D%7D)
