All categories

3 years ago

Is -47 + 19 positive or negative?

Mathematics

2 answers:

andre [41]3 years ago

4 0

Answer:

It would be negative

Step-by-step explanation:

-49+19 would be -28

ivanzaharov [21]3 years ago

4 0

Your answer will be Negative

You might be interested in

Which equation is the inverse of y=2x^2-8

shusha [124]

Step-by-step explanation:

In order to get the inverse of equation, we will interchange the variables and solve for x and y as follows.

$y = 2x^{2} - 8$

whereas, $y + 8 = 2x^{2}$

or x = $\sqrt{\frac{y+8}{2}}$

Now, on interchanging the variable we will get the equation as follows.

$x = 2y^{2} - 8$

$x + 8 = 2y^{2}$

y = $\sqrt{\frac{x+8}{2}}$

4 0

3 years ago

Read 2 more answers

Ben says the angle is an acute angle. Jeff says the angle is less than a straight angle. Explain whether their statements are co

Dahasolnce [82]

Answer:

sometimes, if their average angle is over 45 degrees

never are 2 obtuse angles summing to 180 degrees

always. two 90 degree angles always sum to 180 which is a straight line

7 0

3 years ago

Please help find the perimeter?

erastovalidia [21]

Just use distance formula for each point and plug it in p=a+b+c

6 0

4 years ago

4/7= 5/p. What is P? Pleas solve and show you r work!

vodka [1.7K]

This is a proportion. First you take the numerator times the denominator that is already solved. In this case you will take 5 times 7 and get 35. You then take 35 divided by 4 and get your answer.

8 0

3 years ago

Find values of  that satisfy the equation for 0º    360º and 0  θ  2 . Give answers in degrees and radians.

suter [353]

Answer:

$\theta = 30^\circ, 330^\circ$

$\theta = \frac{\pi}{6}, \frac{11\pi}{6}$

Step-by-step explanation:

Given [Missing from the question]

Equation:

$cos\theta = \frac{\sqrt 3}{2}$

Interval:

$0 \le \theta \le 360$

$0 \le \theta \le 2\pi$

Required

Determine the values of $\theta$

The given expression:

$cos\theta = \frac{\sqrt 3}{2}$

... shows that the value of $\theta$ is positive

The cosine of an angle has positive values in the first and the fourth quadrants.

So, we have:

$cos\theta = \frac{\sqrt 3}{2}$

Take arccos of both sides

$\theta = cos^{-1}(\frac{\sqrt 3}{2})$

$\theta = 30$ --- In the first quadrant

In the fourth quadrant, the value is:

$\theta = 360 -30$

$\theta = 330$

So, the values of $\theta$ in degrees are:

$\theta = 30^\circ, 330^\circ$

Convert to radians (Multiply both angles by $\pi/180$ )

So, we have:

$\theta = \frac{30 * \pi}{180}, \frac{330 * \pi}{180}$

$\theta = \frac{\pi}{6}, \frac{33 * \pi}{18}$

$\theta = \frac{\pi}{6}, \frac{11 * \pi}{6}$

$\theta = \frac{\pi}{6}, \frac{11\pi}{6}$

8 0

3 years ago