Answer:
(a) The probability that a single randomly selected value lies between 158.6 and 159.2 is 0.004.
(b) The probability that a sample mean is between 158.6 and 159.2 is 0.0411.
Step-by-step explanation:
Let the random variable <em>X</em> follow a Normal distribution with parameters <em>μ</em> = 155.4 and <em>σ</em> = 49.5.
(a)
Compute the probability that a single randomly selected value lies between 158.6 and 159.2 as follows:

*Use a standard normal table.
Thus, the probability that a single randomly selected value lies between 158.6 and 159.2 is 0.004.
(b)
A sample of <em>n</em> = 246 is selected.
Compute the probability that a sample mean is between 158.6 and 159.2 as follows:

*Use a standard normal table.
Thus, the probability that a sample mean is between 158.6 and 159.2 is 0.0411.
The experimental probability is
(number of times it stopped over Sect. 2) / (total number of times you tried it)
Number of times it stopped in Section-2: 36
Total number of times you tried it: (20 + 36 + 24) = 80
Experimental probability of Section-2 = 36/80 = 9/20 = 45%
Both the heads and tails will have a probability of 0.5 with a fair coin. ... TO find probability that foe the 7th toss head appears exactly 4 times.
Answer:
can you get a better picture it is hard to see
Step-by-step explanation: