Answer:
Q1: 1.67 L.
Q2: Saturated solution.
Explanation:
<u><em>Q1:</em></u>
- We have the role that the no. of millimoles before dilution is equal to the no. of millimoles after dilution.
<em>(MV) before dilution = (MV) after dilution</em>
M before dilution = 10.0 M, V before dilution = 0.5 L.
M after dilution = 3.0 M, V after dilution = ??? L.
<em>∴ V after dilution = (MV) before dilution / M after dilution</em> = (10.0 M)(0.5 L) / (3.0 M) =<em> 1.67 L.</em>
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<u><em>Q2:</em></u>
From the given curve, it is clear that the solubility of sodium nitrate at 35.0°C is 100 g per 100 g of water.
<em>So, the mentioned solution is a saturated solution at this T.</em>
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<em>A saturated solution is a chemical solution containing the maximum concentration of a solute dissolved in the solvent.</em>
