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3 years ago

Need Help ASAP- Chemistry

Chemistry

1 answer:

jarptica [38.1K]3 years ago

4 0

Answer:

Q1: 1.67 L.

Q2: Saturated solution.

Explanation:

Q1:

We have the role that the no. of millimoles before dilution is equal to the no. of millimoles after dilution.

(MV) before dilution = (MV) after dilution

M before dilution = 10.0 M, V before dilution = 0.5 L.

M after dilution = 3.0 M, V after dilution = ??? L.

∴ V after dilution = (MV) before dilution / M after dilution = (10.0 M)(0.5 L) / (3.0 M) = 1.67 L.

Q2:

From the given curve, it is clear that the solubility of sodium nitrate at 35.0°C is 100 g per 100 g of water.

So, the mentioned solution is a saturated solution at this T.

A saturated solution is a chemical solution containing the maximum concentration of a solute dissolved in the solvent.

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Consider a solution containing 0.100 M fluoride ions and 0.126 M hydrogen fluoride. The concentration of fluoride ions after the

Nataliya [291]

Answer: The concentration of fluoride ions after the addition of 9.00 mL of 0.0100 M HCl to 25.0 mL of this solution is 0.0709 M.

Explanation:

Given: Concentration of hydrogen fluoride = 0.126 M

Concentration of fluoride ions = 0.1 M

Volume of HCl = 9.0 mL

Concentration of HCl = 0.01 M

Volume of HCl = 25.0 mL

Moles of $F^{-}$ ions are calculated as follows.

$Moles of F^{-} = molarity \times volume\\= 0.1 M \times 0.025 L\\= 0.0025 mol$

Moles of HF are as follows.

$Moles of HF = Molarity \times Volume\\= 0.126 M \times 0.025 L\\= 0.00315 mol$

Moles of HCl are as follows.

$Moles of HCl = Molarity \times volume\\= 0.01 M \times 0.009 L\\= 0.00009 mol$

Now, reaction equation with initial and final moles will be as follows.

$H^{+} + F^{-} \rightarrow HF$

Initial: 0.00009 0.0025 0.00315

Equilibrium: (0.0025 - 0.00009) (0.00315 + 0.00009)

= 0.00241 = 0.00324

Total volume = (9.00 mL + 25.0 mL) = 34.0 mL = 0.034 L

Hence, concentration of fluoride ions is calculated as follows.

$Concentration = \frac{moles}{volume}\\= \frac{0.00241 mol}{0.034 L}\\= 0.0709 M$

Thus, we can conclude that concentration of fluoride ions after the addition of 9.00 mL of 0.0100 M HCl to 25.0 mL of this solution is 0.0709 M.

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Answer:

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Explanation:

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