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Misha Larkins [42]
3 years ago
11

A compound contains 47.08% carbon, 6.59% hydrogen and 46.33% chlorine by mass. what is the empirical formula for the compound.

Chemistry
1 answer:
vagabundo [1.1K]3 years ago
7 0
Assume there is 100 grams of the compound. The amounts of each elements would be: 47.08 g C, 6.59 g H and 46.33 g Cl. Convert them to moles.

mol C: 47.08 g * 1 mol/12 g = 3.9233
mol H: 6.59 g * 1mol/1g = 6.59
mol Cl: 46.33 g * 1mol/35.45 g = 1.3069

Divide the smallest amount of moles to each moles of the elements:
C: 3.9233/1.3069 = 3
H: 6.59/1.3069 = 5
Cl: 1.3069/1.3069 = 1

Therefore, the empirical formula of the compound is C₃H₅Cl.
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tatyana61 [14]

Answer: (3) They have different masses and the same charges.

Explanation:

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In the specific case of  <u>electrons</u> and <u>protons</u>, <u>both have the same charge, but electrons have the opposite sign</u>. This means a proton has an electric charge of  +1 and an electron has an electric charge of  −1.

On the other hand, <u>protons have more mass than electrons.</u> In fact, thetex]mass of an electron is about approximately \frac{1}{2000} the mass of a proton, this means these negative charged particles contribute almost nothing to the total mass of an atom (unlike protons, which together with neutrons, make up virtually all of the mass of an atom).

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5 0
3 years ago
An unidentified compound contains only phosphorous and fluorine, meaning we could write its formula as PxFy. Heating 0.2324 g of
cricket20 [7]

Answer:

The molecular formula of the compound is P2F4

Explanation:

Step 1: Data given

Mass of the compound  = 0.2324 grams

Volume of container = 378 mL

Pressure at 77 °C = 97.3 torr

The gaseous PxFy was then reacted with an aqueous solution of calcium chloride, and all of the fluorine was converted to 0.2631 g of CaF2.

Molar mass CaF2 = 78.07 g/mol

Step 2: Calculate moles CaF2

Moles CaF2 = 0.2631 g/ 78.07 g/mol=0.003370

Step 3: Calculate moles F

For every 1 mol CaF2 we have 1 mol Ca2+ and 2 moles F-

moles F- = 2 * 0.003370=0.006740

Step 4: Calculate mass of F

mass F =  0.006740 mol * 19.00 g/mol=0.1281 g

Step 5: Calculate mass of P

mass P = mass of compound - mass of F = 0.2324 - 0.1281 =0.1043 g

Step 6: Calculate moles P

moles P = 0.1043 g/ 30.97 g/mol=0.003368 moles

Step 7: Calculate mol ratio

We divide by the smallest amount of moles

P: 0.003368/0.003368 =1

F: 0.006740/ 0.003368 =2

The empirical formula is PF2

The empirical formula has a molar mass of 68.97 g/mol

Step 8: Calculate moles of compound

p*V = n*R*T

n = (p*V)/(R*T)

⇒ with p = the pressure of the gas = 97.3 torr = 97.3/760 = 0.128 atm

⇒ with V = the volume of the gas = 0.378 L

⇒ with R = the gas constant = 0.08206 L*atm/K*mol

⇒ with T = the temperature = 77.0 °C = 350 Kelvin

Number of moles =(0.128 *0.378)/(0.08206*350)

Number of moles =

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Step 9: Calculate molar mass

Molar mass = mass / moles

Molar mass = 0.2324 grams / 0.00168 moles

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Step 10: Calculate the molecular formula

138.0 / 68.97 = 2

2*(PF2) = P2F4

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4 0
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kondor19780726 [428]

Answer:

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Explanation:

diluting 25 to 100 cuts the M to 1/4 of the original

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