Answer:
21.19 L or 5.6 gallons
Explanation:
Data Given
initial volume V1 = 4.50 gallons
convert volume from gallons to L
1 gallon = 3.78541 L
4. 50 gallon = 3.785 L x 4.50
So,
initial volume V1 = 17.03 L
final Volume V2 = ?
initial Temperature T1 = 80° F
convert Temperature to Kelvin
T1 = ( 80° F -32) / 1.8 +273
T1 = 26.7° C + 273 = 299.7 K
final Temperature T2 = 100° C
convert Temperature to Kelvin
T2 = 100° C + 273 = 373 K
Solution:
This problem will be solved by using charles' law equation at constant pressure.
The formula used
V1 / T1 = V2 / T2
As we have to find out volume, so rearrange the above equation
V2 = V1 x T2 / T1
Put value from the data given and conversion information in above equation
V2 = 17.03 L x 373 K / 299.7 K
V2 = 21. 19 L
So the final volume of Methane gas = 21.19 L
Or for Volume in gallons
1 L = 0.26
21.19 x 0.264 = 5.6 gallons
