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Nastasia [14]
3 years ago
6

PLZ HURRY I NEED SOME HLEP

Chemistry
2 answers:
Troyanec [42]3 years ago
6 0

citric acid is in most foods

Igoryamba3 years ago
5 0

acetic acids and citric acids are safe to eat

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Which of the following could be said about ecological footprints?
Thepotemich [5.8K]
<span>A. Exact ecological footprints are often difficult to calculate, but estimates can be useful in comparing populations.

</span>Which of the following could be said about ecological footprints? <u /> <u>Exact ecological footprints are often difficult to calculate, but estimates can be useful in comparing populations.</u><u />


NOT:
b. Ecological footprints can't be used to determine carrying capacity.
C. Ecological footprints don't take into account resources needed to absorb and manage wastes.
<span>D. The average ecological footprints for various countries are nearly identical.</span>
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3 years ago
I need helpppp plzzzz
Inessa [10]

Answer:

at first i would like to tell which class

Explanation:

125000 is the answwr

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3 years ago
Which of these features is usually found where mountains exist next to the ocean?
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Fjords are usually found where mountains exist next to the ocean.

So the correct answer is C.

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Davinia.

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3 years ago
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Practice Problem 07.61 Draw the major product that is obtained when (2S,3S)-2-Bromo-3-phenylbutane is treated with sodium ethoxi
schepotkina [342]

Answer:

Look at the picture.

Explanation:

(2S,3S)-2-Bromo-3-phenylbutane will undergo E2 reaction and form trans product of elimination due to its thermodynamic stability.

7 0
3 years ago
Suppose 550.mmol of electrons must be transported from one side of an electrochemical cell to another in 49.0 minutes. Calculate
nekit [7.7K]

Answer:

18.0 Ampere is the size of electric current that must flow.

Explanation:

Moles of electron , n = 550 mmol = 0.550 mol

1 mmol = 0.001 mol

Number of electrons = N

N=N_A\times n

Charge on N electrons : Q

Q = N\times 1.602\times 10^{-19} C

Duration of time charge allowed to pass = T = 49.0 min = 49.0 × 60 seconds

1 min = 60 seconds

Size of current : I

I=\frac{Q}{T}=\frac{N\times 1.602\times 10^{-19} C}{49.0\times 60 seconds}

=\frac{n\times N_A\times 1.602\times 10^{-19} C}{49.0\times 60 seconds}

I=\frac{0.550 mol\times 6.022\times 10^{23} mol^{-1}\times 1.602\times 10^{-19} C}{49.0\times 60 seconds}=18.047 A\approx 18.0 A

18.0 Ampere is the size of electric current that must flow.

3 0
3 years ago
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