Answer:
C. 12.8 liters.
Explanation:
The Standard Temperature and Pressure (STP) of a gas are 273.15 K and 100 kilopascals. From Avogadro's Law, a mole of carbon dioxide contains 
molecules. If we suppose that carbon dioxide behaves ideally, then the equation of state for ideal gas is:
(1)
(1b)
Where:
- Pressure, measured in pascals.
- Volume, measured in liters.
- Amount of molecules, no unit.
- Avogadro's number, no unit.
- Ideal gas constant, measured in pascal-liters per mole-Kelvin.
- Temperature, measured in Kelvin.
If we know that 
, 
, 
, 
and 
, then the volume of carbon dioxide at STP is:
Therefore, the correct answer is C.
A thermochemical reaction is a chemical reaction with an additional information of the heat of reaction. For example, this is the thermochemical reaction for the combustion of hydrogen gas:
H₂ (g) + 1/2 O₂ (g) → H₂O (l) ΔH = -285.8 kJ
The coefficient 1/2 represents the number of moles of O₂ needed to combust 1 mole of H₂ gas in order to yield one mole of water.
exactly 1 molecule of water is H2O just 1 is the answer
Answer: Objects with like charge repel each other.
2SO₂+O₂⇒2SO₃ ΔH=-197 kJ
<h3>Further explanation</h3>
Based on the principle of Hess's Law, the change in enthalpy of a reaction will be the same even though it is through several stages or ways
Reaction
2SO₂+O₂⇒2SO₃
Given :
1. S(s)+O₂(g)→SO₂(g) ΔH = -297 kJ
Reverse
SO₂(g) ⇒S(s)+O₂(g ΔH = +297 kJ
(sign change to +) x 2
2SO₂(g) ⇒2S(s)+2O₂(g ΔH = +594 kJ
2.2S(s)+3O2(g)→2SO3(g) ΔH=-791kJ
Add both reactions and remove/subtract the same compound for different sides
1. 2SO₂(g) ⇒2S(s)+2O₂(g) ΔH = +594 kJ
2.2S(s)+3O₂(g)→2SO₃(g) ΔH=-791kJ
--------------------------------------------------------+
2SO₂+O₂⇒2SO₃ ΔH=-197 kJ
