<em>Answer:</em>
<h3><em>Answer:</em><em> </em><em>well</em><em> </em><em> </em></h3>
<em>b. a type of gas is evolved ( hydrogen gas</em><em> )</em>
<em> </em>
Explanation:
When we increase the temperature of a substance then there will occur an increase in the kinetic energy of its molecules.
Also, K.E = 
So, kinetic energy is directly proportional to the temperature.
Hence, when temperature and pressure are kept the same for both oxygen and hydrogen gas then values of their kinetic energy will be the same irrespective of their masses.
Thus, we can conclude that kinetic energy of oxygen molecule is the same as compared to hydrogen molecule.
Answer:
V CH4(g) = 190.6 L
Explanation:
assuming ideal gas:
∴ STP: T =298 K and P = 1 atm
∴ R = 0.082 atm.L/K.mol
∴ moles (n) = 7.80 mol CH4(g)
∴ Volume CH4(g) = ?
⇒ V = RTn/P
⇒ V CH4(g) = ((0.082 atm.L/K.mol)×(298 K)×(7.80 mol)) / (1 atm)
⇒ V CH4(g) = 190.6 L
Determining the identity of substances is a critical part of chemistry because once the substance's identity is known, we can predict its behavior and understand the scenarios that it is involved in better.
For example, consider an industrial pipe where fouling (scaling) is occurring. If the compounds present in the scales are identified, steps may be taken to prevent and remove the scaling. This is one of many examples where identifying chemical substances is of high importance.
