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3 years ago

What is 3 dived by 1/2?

Mathematics

2 answers:

Vesna [10]3 years ago

8 0

Answer:

Step-by-step explanation:

AURORKA [14]3 years ago

6 0

Answer:

Step-by-step explanation:

3÷1/2

You would flip the denominator and numerator and multiply it by the first number.

3×2/1

6/1

Hope this helps!!!

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Solve the inequality for x<br><br> 20x > 8(4x - 5) - 20

UNO [17]

Hi there! I can help you with this! First, let's combine like terms and do everything for the right side of the problem. When you do the distributive property, you get 32x - 40. Combine like terms and you'll get 32x - 60. Now, the inequality is 20x = 32x - 60. First, let's subtract 32x from both sides to get the integer by itself. When you do that, you get -12x = -60. Now, divide each side by -12 to isolate the "x". -60/-12 is 5. Let's plug it in. 20 * 5 is 100. 32 * 5 is 160. 160 - 60 is 100. 100 = 100. There. x = 5.

4 0

3 years ago

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A boy needs to grill 13 pounds of meat for a cookout. Determine the Maximum cost per pound that he can afford if he wants to spe

marissa [1.9K]

Answer:

$5.38 per pound

Step-by-step explanation:

70/13=5.384615

5.38x13=69.94

6 0

3 years ago

Write as a product of two polynomials.<br><br> 2(3-b)+5(b-3)^2

viktelen [127]

Answer:

$5b^{2}-32b+51$

Step-by-step explanation:

$2(3-b)+5(b-3)^{2}$

$=6-2b+5b^{2}-30b+45$

$=5b^{2}-32b+51$

4 0

2 years ago

What is being done to the variable in the equation 3 + g = -9?

almond37 [142]

Answer:

its A

Step-by-step explanation:

not gonna explain it cause I dont have to ._. plus it wasnt that hard

4 0

3 years ago

Question regarding logarithms.

Eddi Din [679]

$5^{x-2}-7^{x-3}=7^{x-5}+11\cdot5^{x-4}\\\\5^{x-2}-7^{x-2-1}=7^{x-2-3}+11\cdot5^{x-2-2}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\5^{x-2}-\dfrac{7^{x-2}}{7^1}=\dfrac{7^{x-2}}{7^3}+11\cdot\dfrac{5^{x-2}}{5^2}\\\\5^{x-2}-\dfrac{1}{7}\cdot7^{x-2}=\dfrac{1}{343}\cdot7^{x-2}+\dfrac{11}{25}\cdot5^{x-2}\\\\-\dfrac{1}{7}\cdot7^{x-2}-\dfrac{1}{343}\cdot7^{x-2}=\dfrac{11}{25}\cdot5^{x-2}-5^{x-2}\\\\\left(-\dfrac{1}{7}-\dfrac{1}{343}\right)\cdot7^{x-2}=\left(\dfrac{11}{25}-1\right)\cdot5^{x-2}$

$\left(-\dfrac{49}{343}-\dfrac{1}{343}\right)\cdot7^{x-2}=-\dfrac{14}{25}\cdot5^{x-2}\\\\-\dfrac{50}{343}\cdot7^{x-2}=-\dfrac{14}{25}\cdot5^{x-2}\qquad\text{multiply both sides by}\ \left(-\dfrac{25}{14}\right)\\\\\dfrac{50\cdot25}{343\cdot14}\cdot7^{x-2}=5^{x-2}\qquad\text{divide both sides by}\ 7^{x-2}\\\\\dfrac{25\cdot25}{343\cdot7}=\dfrac{5^{x-2}}{7^{x-2}}\qquad\text{use}\ \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}$

$\dfrac{5^2\cdot5^2}{7^3\cdot7}=\left(\dfrac{5}{7}\right)^{x-2}\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\\dfrac{5^4}{7^4}=\left(\dfrac{5}{7}\right)^{x-2}\\\\\left(\dfrac{5}{7}\right)^4=\left(\dfrac{5}{7}\right)^{x-2}\iff x-2=4\qquad\text{add 2 to both sides}\\\\\boxed{x=6}$

6 0

3 years ago

Read 2 more answers