D1,..,d9 = 0,0,2,2,2,3,4,6,8 //there are 9 values, in ascending order
Q2 (median) = d5 = 2 //value in the middle
Q1 = (d2+d3) / 2 = (0+2)/2 = 1
(Q1 is middle value of d1,d2,d3,d4, but there is no middle element among four elements, that is why arithmetic mean is taken)
Q3 = (d7+d8) / 2 = (4+6)/2 = 5
interquantlie range = IQR = Q3 - Q1 = 5 -1 = 4
answer: 4
I believe it’s D I’m not 100 percent sure tho
Answer:
Solution given
side 1:1 units
side 2=4 units
height =3 units
we have
Area of trapezoid =½*height(side1+side2)
=½*3(1+4)=15/2
<u>areas of the </u><u>trapezoid</u><u> </u><u>is</u><u> </u><u>1</u><u>5</u><u>/</u><u>2</u><u> </u><u>or</u><u> </u><u>7</u><u>.</u><u>5</u><u> </u><u>square</u><u> </u><u>units</u><u>.</u>
Ladder=10 feet
bottom of ladder=4 feet
hight of tree=x
by using pythogorean theorem
h^2=altitude^2+altitude^2
10^2=4^2+x^2
100=16+x^2
84=x^2
taking sqrt on both sides
9.2=x
hope this helps