Question

1. Complete the following

Answer 1

Answer:

$\large \boxed{\text{0.603 mol}}$

Explanation:

We must do the conversions

mass of C₆H₁₂O₆ ⟶ moles of C₆H₁₂O₆ ⟶ moles of O₂

We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.

Mᵣ:        180.16

           C₆H₁₂O₆ + 6O₂ ⟶ 6CO₂ + 6H₂O

m/g:        18.1

(a) Moles of C₆H₁₂O₆

$\text{Moles of C _{6} H _{12} O}_{6} = \text{18.1 g C _{6} H _{12} O}_{6}\times \dfrac{\text{1 mol C _{6} H _{12} O}_{6}}{\text{180.16 g C _{6} H _{12} O}_{6}}\\\\= \text{0.1005 mol C _{6} H _{12} O}_{6}$

b) Moles of O₂

$\text{Moles of O}_{2} =\text{0.1005 mol C _{6} H _{12} O}_{6} \times \dfrac{\text{6 mol O}_{2}}{\text{1 mol C _{6} H _{12} O}_{6}} = \text{0.603 mol O}_{2}\\\\\text{The reaction requires \large \boxed{\textbf{0.603 mol}} of oxygen}$