Chemicals dissolved in water. Calcite is a good example, if I'm not mistaken.
Answer: 4.25
Explanation: CsOH=Cs+
pOH= -log10
= -log10(5.6*10^-5)
= -log10(5.6*10^-5)=-(-4.25)
=4.25
1. 5 ethyl, 2 methyl octane
2. 1 ethyl, 2 methyl cyclopentane
3. 3,3,5,5- tetrafluoro heptane
4. 3,4-dimethyl hexene
5. 3,4-dimethyl cyclobutene
6. 3,5 diisopropyl cyclohexene
7. 3,3,4 trimethyl pentyne
8. 2,6 dibromo phenol
keep in mind that between 4-7, there could be #1 in front of the main name. for example with #4: 3,4-dimethyl-1- hexene. this honestly depends on the professor how he/she likes it. It is not necessary because if the number is not specified, it is assumed is #1
Answer:
Every sample of a given substance has identical intensive properties because every sample has the same composition
