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sveticcg [70]
1 year ago
12

Calculate the ph resulting from mixing 15. 00 ml of 0. 800 m hio3 (pka = 0. 77) with 45. 00 ml of 0. 0200 m naoh.

Chemistry
1 answer:
QveST [7]1 year ago
4 0

By mixing 15.00ml of 0.800m HIO3 (pka = 0.77) with 45.00ml of 0.0200 m NaOh gives a pH = -0.32

The balanced acid-base reaction equation between iodic acid and NaOH is

HIO3 + NaOH -> H20 + NaIO3

What are the functions of buffer system?

In an aqueous solution, a weak Bronsted acid reversibly dissociates to produce weak conjugate bases and hydrogen ions.

The hydrogen ion molarity in the solution and the conjugate pair's molar ratio are related by the K an expression of the weak acid.

The molar ratio will be shifted more in favour of the weak conjugate base if a tiny amount of strong base is added to the weak acid solution. A buffer solution will be produced as a result of the pH of the solution shifting upward.

Hence the pH value is -0.32

Learn more about buffer system,

brainly.com/question/22821585

# SPJ4

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Salt water can be desalinated by distillation. How much energy is needed to convert 175 g of salt water at 28.0 °C to water vapo
Vinil7 [7]

Answer:

\Delta H=4.63x10^{5}J=463kJ

Explanation:

Hello,

In this case, we find the following states:

a. Liquid salt water at 28.0 °C.

b. Liquid salt water at 102.5 °C.

c. Vapor salt water at 102.5 °C.

The first process (1) is to heat the liquid water from 28.0 °C to 102.5 °C and the second one (2) to vaporize the liquid salt water. In such a way, each process has an amount of energy that when added, yields the total energy for the process as shown below:

\Delta H=\Delta H_1+\Delta H_2\\\Delta H=mCp\Delta T+m\Delta _VH\\\Delta H=175g*5.19\frac{J}{g*K}*(375.65K-301.15K)+175g*2.26\frac{kJ}{g} *\frac{1000J}{1kJ} \\\Delta H=4.63x10^{5}J=463kJ

Best regards.

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