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sveticcg [70]
1 year ago
12

Calculate the ph resulting from mixing 15. 00 ml of 0. 800 m hio3 (pka = 0. 77) with 45. 00 ml of 0. 0200 m naoh.

Chemistry
1 answer:
QveST [7]1 year ago
4 0

By mixing 15.00ml of 0.800m HIO3 (pka = 0.77) with 45.00ml of 0.0200 m NaOh gives a pH = -0.32

The balanced acid-base reaction equation between iodic acid and NaOH is

HIO3 + NaOH -> H20 + NaIO3

What are the functions of buffer system?

In an aqueous solution, a weak Bronsted acid reversibly dissociates to produce weak conjugate bases and hydrogen ions.

The hydrogen ion molarity in the solution and the conjugate pair's molar ratio are related by the K an expression of the weak acid.

The molar ratio will be shifted more in favour of the weak conjugate base if a tiny amount of strong base is added to the weak acid solution. A buffer solution will be produced as a result of the pH of the solution shifting upward.

Hence the pH value is -0.32

Learn more about buffer system,

brainly.com/question/22821585

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What kind of reaction is 21,02 → 2H,0 + 0,2
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A scientist stores a very large number of particles in a container. In order to determine the number of particles, the scientist
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6 0
2 years ago
Express the following in liters at STP:<br><br><br><br> 6.62 x 10-3 moles HF
serious [3.7K]

Answer:

The volume of 6.62×10⁻³moles of HF at STP is 148.38×10⁻³ L

Explanation:

Given data:

Number of moles of HF =  6.62×10⁻³ mol

Volume of HF in litter at STP = ?

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

Standard temperature = 273 K

Standard pressure = 1 atm

Now we will put the values in formula.

1 atm × V = 6.62×10⁻³mol ×0.0821 atm.L/ mol.K   × 273 K

V = 6.62×10⁻³mol ×0.0821 atm.L/ mol.K   × 273 K  / 1 atm

V = 148.38×10⁻³ L

Thus, the volume of 6.62×10⁻³moles of HF at STP is 148.38×10⁻³ L.

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3 years ago
Which of the following is a metal?
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A.................. I think the answer

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