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1 year ago

Calculate the ph resulting from mixing 15. 00 ml of 0. 800 m hio3 (pka = 0. 77) with 45. 00 ml of 0. 0200 m naoh.

Chemistry

1 answer:

QveST [7]1 year ago

4 0

By mixing 15.00ml of 0.800m HIO3 (pka = 0.77) with 45.00ml of 0.0200 m NaOh gives a pH = -0.32

The balanced acid-base reaction equation between iodic acid and NaOH is

HIO3 + NaOH -> H20 + NaIO3

What are the functions of buffer system?

In an aqueous solution, a weak Bronsted acid reversibly dissociates to produce weak conjugate bases and hydrogen ions.

The hydrogen ion molarity in the solution and the conjugate pair's molar ratio are related by the K an expression of the weak acid.

The molar ratio will be shifted more in favour of the weak conjugate base if a tiny amount of strong base is added to the weak acid solution. A buffer solution will be produced as a result of the pH of the solution shifting upward.

Hence the pH value is -0.32

Learn more about buffer system,

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Answer:

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Explanation:

Given data:

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Calculate the maximum KE and velocity of an electron from zinc by a 275nm photon

Dmitry [639]

Answer:

Kinetic energy: $6.024*10^{-20}$

Velocity: $3.64*10^{5}$

Explanation:

From the equations of the photo-electric effect,

We know:

$hv=hv_0+K.E$

Where,

1. $h$ is the Planck's constant which is $6.626*10^{-34}$

2. $v,v_0$ are the frequency of light emitted and threshold frequencies respectively.

3. $K.E$ is the kinetic energy of the electrons emitted.

By fact, we come to know that the threshold frequency of Zn is 300nm

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1. $c$ is the speed of light $=3*10^8$

2. $d$ is the wavelength.

Thus,

$\frac{hc}{d}=\frac{hc}{d_0}+K.E\\K.E=\frac{hc}{d}-\frac{hc}{d_0}\\K.E=hc*(\frac{1}{d}-\frac{1}{d_0})\\K.E=6.626*10^{-34}*3*10^8*(\frac{1}{275*10^{-9}}-\frac{1}{300*10^{-9}})\\K.E=6.024*10^{-20}kgm^2s^{-2}$

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