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3 years ago

Filtration and dialysis are techniques that rely on differences in particle size to separate mixture components. True False

Chemistry

2 answers:

bazaltina [42]3 years ago

6 0

Answer: True

Explanation:

Filtration and dialysis are analytical techniques which are used to separate the particles present in the solution.

The particles that is having a bigger size will be left at the bottom in the solution and the smaller particles will be at the top.

This is because the smaller particles are light in weight and large weight are heavier. Both of the methods are used as a purification technique for the separation of impurities from the solution based on the particle size.

soldier1979 [14.2K]3 years ago

3 0

This is true. Think about when you make pasta. The colander acts as a filter and doesn't let the past a through but allows the extra water to escape because the pasta is too big to fit.

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How does ground water become polluted

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True or false? The empirical formula of a compound is the simplest formula that shows the numerical relationship of the elements

Delicious77 [7]

Answer:

True

Explanation:

I think it’s true because the empirical formula of a compound is actually the simplest formula that shows the numerical relationship of the elements in the compound.

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What is the average atomic mass of beanium

Amiraneli [1.4K]

Beanium or signically Bn

$\\ \sf\ast\Rrightarrow Atomic\:Mass=137.327u$

Lets simplify with significant figures

$\\ \sf\ast\Rrightarrow 137.33u$

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3 years ago

QUESTION 21 The combustion of ammonia in the presence of excess oxygen yields NO 2 and H 2O: 4 NH 3 (g) 7 O 2 (g) 4 NO 2 (g) 6 H

Harrizon [31]

Answer:

The answer to your question is 47.44 g of Oxygen

Explanation:

Data

mass of Ammonia = 14.4 g

mass of Oxygen = ?

Balanced chemical reaction

4NH₃ + 7O₂ ⇒ 4NO₂ + 6H₂O

Process

1.- Calculate the molar mass of Ammonia

NH₃ = 4[(1 x 14) + (3 x 1)] = 4[14 + 3] = 4[17] = 68 g

2.- Calculate the molar mass of Oxygen

O₂ = 7[16 x 2] = 7[32] = 224 g

3.- Use proportions to calculate the mass of Oxygen

68g of NH₃ --------------------- 224 g of O₂

14.4 g of NH₃ ----------------- x

x = (14.4 x 224) / 68

x = 3225.6/ 68

x = 47.44 g

5 0

3 years ago

Using this equation, m1v2=m2v2 , calculate the diluted molarity of 100 mL of a 0.5 M solution when 50 mL of

geniusboy [140]

The molarity of the diluted solution is 0.33 M

From the question given above, the following data were obtained:

Molarity of stock solution (M₁) = 0. 5 M

Volume of stock solution (V₁) = 100 mL

Volume of diluted solution (V₂) = 100 + 50 = 150 mL

<h3>Molarity of diluted solution (M₂) =? </h3>

The molarity of the diluted solution can be obtained by using the dilution formula as illustrated below:

0.5 × 100 = M₂ × 150

50 = M₂ × 150

Divide both side by 150

M₂ = 50 / 150

Therefore, the molarity of the diluted solution is 0.33 M

Learn more: brainly.com/question/24625656

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3 years ago