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3 years ago

An inclined plane is 30 meters long and 2 meters high. What is the mechanical advantage of the inclined plane? MA =

Physics

2 answers:

zalisa [80]3 years ago

6 0

Answer:

15=ma

Explanation:

Bond [772]3 years ago

4 0

In a second class lever, the LF is between the fulcrum load.
Like the first class lever, the MA is an increase in fource and is calculated by dividing the EA by the LA ( EA divided LA = IMA )

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A roadway for stunt drivers is designed for racecars moving at a speed of 40 m/s. A curved section of the roadway is a circular

Fynjy0 [20]

Answer:

Bank angle = 35.34o

Explanation:

Since the road is frictionless,

Tan (bank angle) = V^2/r*g

Where V = speed of the racing car in m/s, r = radius of the arc in metres and g = acceleration due to gravity in m/s^2

Tan ( bank angle) = 40^2/(230*9.81)

Tan (bank angle) = 0.7091

Bank angle = tan inverse (0.7091)

Bank angle = 35.34o

3 0

3 years ago

A gold wire has a cross-sectional area of 1.0 cm^2 and a resistivity of 2.8 × 10^-8 Ω ∙ m at 20°C. How long would it have to be

Karo-lina-s [1.5K]

Answer:

Length, l = 3.57 meters

Explanation:

It is given that,

Area of cross-section of gold wire, $A=1\ cm^2=0.0001\ m^2$

Resistivity of gold wire, $\rho=2.8\times 10^{-8}\ \Omega-m$

Resistance, R = 0.001 ohms

Resistance in terms of length and area is given by :

$R=\rho \dfrac{l}{A}$

$l=\dfrac{RA}{\rho}$

$l=\dfrac{0.001\times 0.0001}{2.8\times 10^{-8}}$

l = 3.57 meters

So, the length of the wire is 3.57 meters. Hence, this is the required solution.

4 0

3 years ago

The data indicate the populations of mammals in the Florida Everglades in different years over the past two decades. The Burmese

soldier1979 [14.2K]

Answer:

C) Burmese pythons lack natural predators and can utilize a wide variety of food sources in the Everglades.

Explanation:

Due to it being an invasive specie (naturally found in South Asia), and also one of the five largest species of snakes in the world, the Burmese pythons lack natural predators in this new territories.

The Burmese viper is also an opportunistic hunter and would eat anything it can overpower, it easily made a wide range of food varieties in these swamps.

8 0

3 years ago

A bat, flying at 5.00 m/s, emits a chirp at 40.0 kHz. If this sound pulse is reflected by a wall, what is the frequency of the e

fredd [130]

Answer:

The answer is below

Explanation:

Firstly, the frequency is received by the wall and then it is reflected and received by the bat.

The frequency received by the wall (f') is given by:

f' = $f(v\pm v_o)/v\\\\$

The - sign is used when the observer is moving away from the source and + sign when the observer is moving towards the source.

Since the bat is moving towards the wall, we use a positive sign. Hence:

f' = $f(v+ v_o)/v\\\\$

The frequency reflected and received by the bat f" is:

f'' = $f'\frac{v}{ (v\pm v_s)}\\\\$

- sign is used when the source moves toward the observer and + is used when the source moves away

since the bat moves towards the wall, then::

f'' = $f'\frac{v}{(v-v_s)} =\frac{f(v+v_o)}{v}*\frac{v}{(v-v_s)} =f\frac{(v+v_o)}{(v-v_s)} \\\\$

v = speed of sound in air = 331 m/s, vo = velocity of observer = 5 m/s, vs = velocity of source = 5 m/s. Therefore:

$f"=f\frac{(v+v_o)}{(v-v_s)} =40\ kHz\frac{(331\ m/s+5\ m/s)}{(331\ m/s+5\ m/s)} \\\\f"=41\ kHz$

3 0

3 years ago

Computer models can be touched. <br> True <br> False

scZoUnD [109]

True. I think.................

5 0

3 years ago

Read 2 more answers