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Sulphur
The missing element is sulphur
Here the compound is composed of element X and chlorine.
it is given,
XCl (6) ----> 6Cl
mass = 13.1%
it is X and Cl = 100%-13.10%
= 86.90%
chlorine = 86.90
X = 13.10
We assume 100g of sample
so according to the above solved data, in 100g of sample we have 86.90 g of chlorine.
now we split that chlorine into two moles of chlorine.
- Every mole of sale has 35.45 grams of sales. 2.451 moles of seal are mine after that.
- We are aware that cl is six times more than X. To find the moles of X, I must divide this number by six.
- we discover that we have 0.4086 moles of X when we divide this by six.
- We obtain those moles of X from 13.10 g of X.
- Given that Mueller masses grams per mole, I can compute the molar mass.
- 13.10 grams of X are contained in 0.4086 moles of X.
- Or, to put it another way, each remote has a molar mass of 32–06 grams.
- The element with this molar mass is sulfur, as I can see from the periodic table.
- Okay, so the element we're looking for in this situation is sulfur.
To learn more about finding missing element visit;
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The answer is vena cava
Hope this helps !!
Answer:
1. The period is 1.74 s.
2. The frequency is 0.57 Hz
Explanation:
1. Determination of the the period.
Spring constant (K) = 30 N/m
Mass (m) = 2.3 Kg
Pi (π) = 3.14
Period (T) =?
The period of the vibration can be obtained as follow:
T = 2π√(m/K)
T = 2 × 3.14 × √(2.3 / 30)
T = 6.28 × √(2.3 / 30)
T = 1.74 s
Thus, the period of the vibration is 1.74 s.
2. Determination of the frequency.
Period (T) = 1.74 s
Frequency (f) =?
The frequency of the vibration can be obtained as follow:
f = 1/T
f = 1/1.74
f = 0.57 Hz
Thus, the frequency of the vibration is 0.57 Hz
Answer:
n = 1.4266
Explanation:
Given that:
refractive index of crystalline slab n = 1.665
let refractive index of fluid is n.
angle of incidence θ₁ = 37.0°
Critical angle 
According to Snell's law of refraction:
At point P ; 
Therefore:
Then maximum value of refractive index n of the fluid is:
n = 1.4266
