If it were possible to move a star towards the earth then its apparent magnitude number would decrease while its absolute magnitude number would stay the same.
Definition of apparent magnitude:
The luminosity of a celestial body (such as a star) as observed from the earth compare absolute magnitude.
So for example, the apparent magnitude of the Sun is -26.7 and is the brightest celestial object we can see from Earth. However, if the Sun were 10 parsecs away, its apparent magnitude would be +4.7, only about as bright as Ganymede appears to us on Earth.
Definition of absolute magnitude:
Absolute magnitude is a measure of the luminosity of a celestial object on an inverse logarithmic astronomical magnitude scale.
To learn more about apparent magnitude here
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1). The equation is: (speed) = (frequency) x (wavelength)
Speed = (256 Hz) x (1.3 m) = 332.8 meters per second
2). If the instrument is played louder, the amplitude of the waves increases.
On the oscilloscope, they would appear larger from top to bottom, but the
horizontal size of each wave doesn't change.
If the instrument is played at a higher pitch, then the waves become shorter,
because 'pitch' is directly related to the frequency of the waves, and higher
pitch means higher frequency and more waves in any period of time.
If the instrument plays louder and at higher pitch, the waves on the scope
become taller and there are more of them across the screen.
3). The equation is: Frequency = (speed) / (wavelength)
(Notice that this is exactly the same as the equation up above in question #1,
only with each side of that one divided by 'wavelength'.)
Frequency = 300,000,000 meters per second / 1,500 meters = 200,000 per second.
That's ' 200 k Hz ' .
Note:
I didn't think anybody broadcasts at 200 kHz, so I looked up BBC Radio 4
on-line, and I was surprised. They broadcast on several different frequencies,
and one of them is 198 kHz !
Explanation:
Since, the rod is present in vertical position and the spring is unrestrained.
So, initial potential energy stored in the spring is 
= 0
And, initial potential gravitational potential energy of the rod is 
.
It is given that,
mass of the bar = 0.795 kg
g = 9.8 
L = length of the rod = 0.2 m
Initial total energy T = 
Now, when the rod is in horizontal position then final total energy will be as follows.
T = 
where, I = moment of inertia of the rod about the end = 
Also, 
where, 
= speed of the tip of the rod
x = spring extension
The initial unstrained length is 
= 0.1 m
Therefore, final length will be calculated as follows.
x' = 
m
Then, x = 
x = m - 0.1 m
= 0.1236 m
k = 25 N/m
So, according to the law of conservation of energy
Putting the given values into the above formula as follows.
v = 2.079 m/s
Thus, we can conclude that tangential speed with which end A strikes the horizontal surface is 2.079 m/s.
Answer:
<h2>
3338.98 kg/m³</h2>
Explanation:
The formula for calculating the relative density of a substance is expressed as
Relative density of a liquid = Density of the liquid /density of water
Given relative density of a liquid = 0.34
Density of water 997kg/m³
Substituting into the formula we have;
Density of the liquid = Relative density of a liquid * density of water
Density of the liquid = 0.34 * 997
Density of the liquid = 3338.98 kg/m³
Answer:
x = 5.29 m
Explanation:
given,
weight of stretch = 37 N
left-hand spring constant (k₁)= 2.7 N/cm
right hand spring constant(k₂)= 4.3 N/ cm
spring are connected in parallel
F = F₁ + F₂
F = k₁x + k₂x
F = (k₁+ k₂)x
37= (4.3+ 2.7)x
7 x = 37
x = 5.29 m
