How many atoms are in 3MgCl2?
1 answer:
You might be interested in
Answer:
D = 43 m
Explanation:
given,
initial velocity = 18 m/s
angle θ = 60°
total horizontal distance covered by the shell is
applying conservation of momentum in horizontal direction
m v₀ cos θ = m₁v₁ + m₂ v₂
m v₀ cos θ = 0.5 m v₂
v₂ = 2 v₀ cos θ.
distance covered by the shell from point of explosion
R' = v t
=
=
=
= R
total distance traveled by the shell is
D =
= 1.5 R
=
D =
= 42.9 ≅ 43 m
D = 43 m
Answer:
The compress of the spring is 0.495.
Explanation:
Given that,
Mass = 50 kg
Spring constant = 8000 N/m
height = 2.0 m
We need to calculate the compress of the spring
Using law of conservation of energy
Where, m = mass
g = acceleration due to gravity
h = height
k = spring constant
x = distance
Put the value into the formula
Hence, The compress of the spring is 0.495.