Answer:
The first frequency of audible sound in the speed sound is 
f = 662 Hz
Explanation:
vs = 344 m/s
x =  52 cm * 1 / 100m = 0.52m
The wave length is the distance between the peak and peak so 
d = 2x
d = 2*0.52 m
d = 1.04 m 
So the frequency in the speed velocity is 
f = 1 / T 
f = vs / x = 344 m/s / 0.52m
f ≅ 662 Hz
 
        
             
        
        
        
Answer:
a
   
b 
    
Explanation:
From the question we are told that  
      The pressure of the water in the pipe is   
 
       The speed of the water  is 
        The original area of the pipe is   
 
        The  new area of the pipe is  ![A_2 = \pi *  \frac{[\frac{d}{2} ]^2}{4}  =  \pi *  \frac{\frac{d^2}{4} }{4} = \pi \frac{d^2}{16}](https://tex.z-dn.net/?f=A_2%20%3D%20%5Cpi%20%2A%20%20%5Cfrac%7B%5B%5Cfrac%7Bd%7D%7B2%7D%20%5D%5E2%7D%7B4%7D%20%20%3D%20%20%5Cpi%20%2A%20%20%5Cfrac%7B%5Cfrac%7Bd%5E2%7D%7B4%7D%20%7D%7B4%7D%20%3D%20%5Cpi%20%5Cfrac%7Bd%5E2%7D%7B16%7D) 
 
          
Generally the continuity equation is mathematically represented as 
        
Here  is the new velocity
 is the new velocity  
So 
         
=>     
=>    
=>    
=>     
Generally given that the height of the original pipe and the narrower pipe are the same , then we will b making use of the  Bernoulli's equation for constant height to calculate the pressure 
This is mathematically represented as 
        
              
Here  is the density of water with value
 is the density of water with value   
 
              ![P_2 =  P_1 + \frac{1}{2} *  \rho [ v_1^2 - v_2^2 ]](https://tex.z-dn.net/?f=P_2%20%3D%20%20P_1%20%2B%20%5Cfrac%7B1%7D%7B2%7D%20%2A%20%20%5Crho%20%5B%20v_1%5E2%20-%20v_2%5E2%20%5D)
=>          ![P_2 =  110 *10^{3} + \frac{1}{2} *  1000 *  [ 1.4 ^2 - 5.6 ^2 ]](https://tex.z-dn.net/?f=P_2%20%3D%20%20110%20%2A10%5E%7B3%7D%20%2B%20%5Cfrac%7B1%7D%7B2%7D%20%2A%20%201000%20%2A%20%20%5B%201.4%20%5E2%20-%205.6%20%5E2%20%5D)
=>          
 
        
             
        
        
        
Λ= V/f 
<span>but change it to represent the speed of light, c </span>
<span>λ= c/f </span>
<span>c = 3.00 x 10^8 m/s </span>
<span>Plug in your given info and solve for λ(wavelength) </span>
<span>λ= 3.00 x 10^8 m/s / 7.5 x 10^14 Hz
(3.00 x 10^8) / (7.5 x 10^14) = 300,000,000 / 750,000,000,000,000 = 0.0000004
Hope this helps :)
</span>
        
                    
             
        
        
        
Answer:
Da=(1/4)Db
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration due to gravity = 9.81 m/s²
When s = Da, t = t

When s = Db, t = 2t

Dividing the two equations

Hence, Da=(1/4)Db