Ask question

Ask question

All categories

Misha Larkins [42]

4 years ago

8

If two things collide, where does the lost energy go? Is it transferred into other forms?

1 answer:

Anuta_ua [19.1K]4 years ago

5 0

Answer:

A perfectly inelastic collision is one in which two objects colliding stick together, becoming a single object. In an inelastic collision, energy is lost to the environment, transferred into other forms such as heat. In the above figure, two objects A and B with the same mass m are 15 m away from each other.

You might be interested in

,how do charged objects react???quiet urgent

son4ous [18]

Any charged object can<span> exert the force upon other objects ... i think tell me if im right</span>

8 0

3 years ago

Read 2 more answers

If you're falling in a forest and there's nobody around, do you ever really crash, or even make a sound?

zalisa [80]

Answer:

yes bc there are branches and twigs surrounding you

Explanation:

♡♡♡please mark as brainliest♡♡♡

7 0

4 years ago

Read 2 more answers

A 0.55-μF capacitor is connected to a 3.5-V battery. How much charge is on each plate of the capacitor?

yan [13]

Answer:

1.925 μC

Explanation:

Charge: This can be defined as the product of the capacitance of a capacitor and the voltage. The S.I unit of charge is Coulombs (C)

The formula for the charge stored in a capacitor is given as,

Q = CV ................... Equation 1

Where Q = charge, C = Capacitor, V = Voltage.

Note: 1 μF = 10⁻⁶ F

Given: C = 0.55 μF = 0.55×10⁻⁶ F, V = 3.5 V.

Substitute into equation 1

Q = 0.55×10⁻⁶×3.5

Q = 1.925×10⁻⁶ C.

Q = 1.925 μC

Hence the charge on the plate = 1.925 μC

6 0

4 years ago

Read 2 more answers

An ideal monatomic gas initially has a temperature of T and a pressure of p. It is to expand from volume V1 to volume V2. If the

yawa3891 [41]

Answer:

Isothermal : P2 = ( P1V1 / V2 ) , work-done $pdv = nRT * In( \frac{V2}{v1} )$

Adiabatic : : P2 = $\frac{P1V1^{\frac{5}{3} } }{V2^{\frac{5}{3} } }$ , work-done =

W = $(3/2)nR(T1V1^(2/3)/(V2^(2/3)) - T1)$

Explanation:

initial temperature : T

Pressure : P

initial volume : V1

Final volume : V2

A) If expansion was isothermal calculate final pressure and work-done

we use the gas laws

= PIVI = P2V2

Hence : P2 = ( P1V1 / V2 )

work-done :

$pdv = nRT * In( \frac{V2}{v1} )$

B) If the expansion was Adiabatic show the Final pressure and work-done

final pressure

$P1V1^y = P2V2^y$

where y = 5/3

hence : P2 = $\frac{P1V1^{\frac{5}{3} } }{V2^{\frac{5}{3} } }$

Work-done

W = $(3/2)nR(T1V1^(2/3)/(V2^(2/3)) - T1)$

Where $T2 = T1V1^(2/3)/V2^(2/3)$

3 0

3 years ago

A chair of weight 125 N lies atop a horizontal floor; the floor is not frictionless. You push on the chair with a force of F = 3

iris [78.8K]

Answer:

N = 148.10N

Explanation:

GIVEN

Weight =125 N

force = 35

angle =42°

since there is no vertical acceleration $a_{y} = 0$ from

free body diagram

$\Sigma fa_{y} = ma_{y} = 0$

$N-W-Fsin42\degree = 0\\\\N= W+Fsin42\\N = 125+35\times 0.66\\N = 148.10 N$

5 0

4 years ago