Answer:
The possible range of wavelengths in air produced by the instrument is 7.62 m and 0.914 m respectively.
Explanation:
Given that,
The notes produced by a tuba range in frequency from approximately 45 Hz to 375 Hz.
The speed of sound in air is 343 m/s.
To find,
The wavelength range for the corresponding frequency.
Solution,
The speed of sound is given by the following relation as :
Wavelength for f = 45 Hz is,
Wavelength for f = 375 Hz is,
So, the possible range of wavelengths in air produced by the instrument is 7.62 m and 0.914 m respectively.
Answer:
Total Resistance in circuit is Fourteen Ohms <u>(14 Ω).</u>
<u></u>
Explanation:
How do we know, if the resistors are connected in series, the total resistance is the <u>sum of all the resistors.</u>
(Important: The total resistance can only be added just when the resistors are <u>connected in series</u>)
Then, total resistance (<em>TR </em>) is the sum of all resistors (<em>T1 + T2</em>, in this case)
TR = T1 + T2
According to problem data, we have:
TR = 8 Ω + 6 Ω
TR = 14 Ω
║Sincerely, ChizuruChan║
<span>Sea breeze can happen during hot summer days because of the
uneven heating rates of water and land.
The land surface heats up faster than the surface of the water during the
day. At this rate, the air above the
land grows warmer than the air atop the ocean. Warmer air is always lighter
than cooler air. As a consequence, warm air is pushed upward causing it to
rise. With this, warmer air rises over the land. As warm air rises over the
land, cooler air over the ocean flows over the land surface to change or
replace the rising warm air.</span>
The bike is maintaining "constant velocity". He's moving at 15 m/s when we see him for the first time, 15 m/s later that day, and 15 m/s next week.
The car starts from zero, and goes 4.0 m/s FASTER each second. After one second, it's going 4.0 m/s. After 2 seconds, it's going 8 m/s. And after 3 seconds, it's going 12 m/s.
This is the point at which the question wants us to compare them ... 3 seconds. The bike is moving at 15 m/s and the car has sped up to 12 m/s. <em>The bike is moving faster than the car.</em>
If we hung around and kept watching for another second, the car would then be moving at 16 m/s, and would be moving faster than the bike. But we lost interest after answering the question, and we left at 3 seconds.
Explanation:
(a) Net force acting on the block is as follows.
or, ma = -mg Sin (\theta)[/tex]
a = 
= 
= -3.35 
According to the kinematic equation of motion,
Distance traveled by the block before stopping is as follows.
s = 
= 
= 21.5 m
According to the kinematic equation of motion,
v = 
0 = 
= 7.16 sec
Therefore, before coming to rest the surface of the plane will slide the box till 7.16 sec.
(b) When the block is moving down the inline then net force acting on the block is as follows.
ma = 
a = 
= 
= 3.35
Kinematics equation of the motion is as follows.
s = 
21.5 m = 
= 
= 3.58 sec
Hence, total time taken by the block to return to its starting position is as follows.
t = 
= 7.16 sec + 3.58 sec
= 10.7 sec
Thus, we can conclude that 10.7 sec time it take to return to its starting position.
