They are different beacause of the stages some you can see and not. And the cells move at different paces
Answer:
E cell = +1.95 V
Explanation:
At Anode : Oxidation reaction takes place
At Cathode : Reduction reaction takes place
The reaction with lower value of reduction potential will undergo Oxidation
E = -1.18 V
This equation undergo oxidation reaction and become:
Anode(Oxidation-Half) :
E = +1.18 V
Cathode(Reduction-Half) :
E =+0.77 V
To balance the reaction multiply reduction-Half with 2.We get :

Note that E is intensive property , do not multiply E of oxidation-half with 2
Ecell = 0.77 -(-1.18)
E = +1.95 V
Answer: The value of acid ionization constant
for acetic acid is 
Explanation:
cM 0 0
So dissociation constant will be:
Give c= 0.85 M and
= 2.4
![pH=-log[H^+]](https://tex.z-dn.net/?f=pH%3D-log%5BH%5E%2B%5D)
Putting in the values we get:
Thus the value of acid ionization constant
for acetic acid is 
The atoms that are the same element are atoms 1 and 2, because they have the same number of protons (option D).
<h3>What is an element?</h3>
Element is one of the simplest chemical substances that cannot be decomposed in a chemical reaction or by any chemical means and made up of atoms all having the same number of protons.
The atoms of an element have the same number of protons, which is the atomic number.
According to the table given above, three atoms and their respective proton, electron and neutron number are given.
It can be said that atoms 1 and 2 are of the same element, because they have the same number of protons.
Learn more about elements at:
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