According to the electron-cloud model of the atom, an orbital is a

Chemistry

2 answers:

Aleks [24]4 years ago

7 0

Answer : Option 4) Region of the most probable electron location.

Explanation : As per the electron cloud model of the atom, an orbital is a region where the probability of finding an electron is highest. According to this model which was used to identify the probable location of the electrons when they go around the nucleus of an atom.

This electron cloud model was different from the older Bohr atomic model by Niels Bohr.

Yakvenalex [24]4 years ago

5 0

According to the electron-cloud model of the atom, an orbital is a "<span>region of the most probable electron location" In this mode, an electron can actually be in two places at once. </span>

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3 Cu + SHNO3 — 3 Cu(NO3)2 + 2 NO + 4 H20

LenaWriter [7]

Considering the reaction stoichiometry, the mass of H₂O that is produced when 11.9 moles of HNO₃ react is 107.1 grams.

<h3>Reaction stoichiometry</h3>

The balanced reaction is:

3 Cu + 8 HNO₃ → 3 Cu(NO₃)₂ + 2 NO + 4 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

Cu: 3 moles
HNO₃: 8 moles
Cu(NO₃)₂: 3 moles
NO: 2 moles
H₂O: 4 moles

The molar mass of the compounds present in the reaction is:

Cu: 63.54 g/mole
HNO₃: 63 g/mole
Cu(NO₃)₂: 187.54 g/mole
NO: 30 g/mole
H₂O: 18 g/mole

Then, by reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of mass of each compound participate in the reaction:

Cu: 3 moles ×63.54 g/mole= 190.62 grams

HNO₃: 8 moles ×63 g/mole= 504 grams

Cu(NO₃)₂: 3 moles ×187.54 g/mole= 562.62 grams

NO: 2 moles ×30 g/mole= 60 grams

H₂O: 4 moles ×18 g/mole= 72 grams

<h3>Mass of H₂O produced</h3>

It is possible to determine the the amount of mass of H₂O produced by a rule of three: if by stoichiometry 8 moles of HNO₃ produce 72 grams of H₂O, if 11.9 moles of HNO₃ react how much mass of H₂O will be formed?

$mass of H_{2}O=\frac{11.9 moles of HNO_{3} x72 grams of H_{2}O}{8 moles of HNO_{3}}$