According to the electron-cloud model of the atom, an orbital is a

Chemistry

2 answers:

Aleks [24]2 years ago

7 0

Answer : Option 4) Region of the most probable electron location.

Explanation : As per the electron cloud model of the atom, an orbital is a region where the probability of finding an electron is highest. According to this model which was used to identify the probable location of the electrons when they go around the nucleus of an atom.

This electron cloud model was different from the older Bohr atomic model by Niels Bohr.

Yakvenalex [24]2 years ago

5 0

According to the electron-cloud model of the atom, an orbital is a "<span>region of the most probable electron location" In this mode, an electron can actually be in two places at once. </span>

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What is the % composition of Carbon in Chromium (iii) Carbonate

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Step 1 - Discovering the ionic formula of Chromium (III) Carbonate

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$Cr^{3+}+CO^{2-}_3\rightarrow Cr_2(CO_3)_3$

Step 2 - Finding the molar mass of the substance

To find the molar mass, we need to multiply the molar mass of each element by the number of times it appears in the formula of the substance and, finally, sum it all up.

The molar masses are 12 g/mol for C; 16 g/mol for O and 52 g/mol for Cr. We have thus:

$\begin{gathered} C\rightarrow3\times12=36 \\ \\ O\rightarrow9\times16=144 \\ \\ Cr\rightarrow2\times52=104 \end{gathered}$

The molar mass will be thus:

$M=36+104+144=284\text{ g/mol}$

Step 3 - Finding the percent composition of carbon

As we saw in the previous step, the molar mass of Cr2(CO3)3 is 284 g/mol. From this molar mass, 36 g/mol come from C. We can set the following proportion:

$\begin{gathered} 284\text{ g/mol ---- 100\%} \\ 36\text{ g/mol ----- x} \\ \\ x=\frac{36\times100}{284}=\frac{3600}{284}=12.7\text{ \%} \end{gathered}$

The percent composition of Carbon is thus 12.7 %.

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