Explanation:
A gas has a temperature of 273.15 K and a pressure of 101.325 kPa. It can be concluded that this gas has reached standard temperature and pressure.
Standard temperature is zero degree celcius which corresponds to 273.15 degree kelvin.
Standard pressure is 760 mmHg which corresponds to 101.325 kPa.
Answer:inform the lab instructor and get instructions
Explanation:
If you come across a chemical in the laboratory which has been wrongly labelled, do not be quick to dilute it or take any further action. The laboratory instructor who may have prepared the reagent himself or has better knowledge about the reagent should be contacted immediately so that he/she can give you instructions about what to do with the wrongly labelled reagent.
Answer:
B)3
Explanation:
I'm assuming the 2 is meant to be smaller. If it were a regular size 2 the answer would be 2 and that isn't an option
Answer: 60.1K
Explanation:
Initial volume of gas V1 = 423.3mL
Initial temperature T1 = 49.2°C
Convert temperature in Celsius to Kelvin
( 49.2°C + 273 = 322.2K)
Final temperature T2 = ?
Final volume V2 = 79mL
According to Charle's law, the volume of a fixed mass of a gas is directly proportional to the temperature.
Mathematically, Charles' Law is expressed as: V1/T1 = V2/T2
423.3mL/322.2 = 79mL/T2
To get the value of T2, cross multiply
423.3mL x T2 = 322.2K x 79mL
423.3mL x T2 = 25453.8
T2 = (25453.8/423.3mL)
T2 = 60.1K
Thus, the new temperature of the gas is 60.1K
Answer:
It should b KNO3
Explanation:
one Potassium (K) and three Nitrite (NO3)
