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mariarad [96]
3 years ago
7

The train station is 37.1 kilometers west of the locksmith. The locksmith is 56.2 kilometers west of the restaurant, and the res

taurant is 42 kilometers west of the radio tower.
Which is closer to the restaurant, the locksmith or the radio tower?
locksmith
radio tower.
Mathematics
2 answers:
jeyben [28]3 years ago
7 0
The train station is closer. Hope this helped!


Georgia [21]3 years ago
4 0
The radio station is closer to the restaurant. Hope this helps. 
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Using the digits 0 to 9, without repetition, fill the blanks.
Alexandra [31]
First angle to the right inside the triangle can be 60
Other angle inside the triangle can be 40
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After eating dinner at a restaurant your bill was $56. You plan to leave a 20% tip. What will your total cost be? (Hint: find th
DerKrebs [107]

Answer: $67.20

Step-by-step explanation:

56 × 0.2 = 11.2

11.2 + 56 = $67.20

3 0
3 years ago
-(x + 8) = -x
White raven [17]

Answer:

Step-by-step explanation:

i can help

Step 1

-(x + 8) = -x  Simplify

Step 2

-(x + 8) = -x  Simplify the sides of the equation

-x-8=-x

Step 3

-x-8=-x  Add x to the sides

-8=0

Step 4

-8=0  Add 8 to the sides

0=8

Answer

No solution

Hope this helps

5 0
3 years ago
Which points on the number line represent the quotients of these expressions? 12 divided by -6 and -15 divided by -3
yaroslaw [1]

Answer:

2,5

Step-by-step explanation:

basta isipin mo BWHAHAHAHAHHA balakadan

4 0
3 years ago
Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y
ludmilkaskok [199]

Answer:

Step-by-step explanation:

Given that:

The differential equation; (x^2-4)^2y'' + (x + 2)y' + 7y = 0

The above equation can be better expressed as:

y'' + \dfrac{(x+2)}{(x^2-4)^2} \ y'+ \dfrac{7}{(x^2- 4)^2} \ y=0

The pattern of the normalized differential equation can be represented as:

y'' + p(x)y' + q(x) y = 0

This implies that:

p(x) = \dfrac{(x+2)}{(x^2-4)^2} \

p(x) = \dfrac{(x+2)}{(x+2)^2 (x-2)^2} \

p(x) = \dfrac{1}{(x+2)(x-2)^2}

Also;

q(x) = \dfrac{7}{(x^2-4)^2}

q(x) = \dfrac{7}{(x+2)^2(x-2)^2}

From p(x) and q(x); we will realize that the zeroes of (x+2)(x-2)² = ±2

When x = - 2

\lim \limits_{x \to-2} (x+ 2) p(x) =  \lim \limits_{x \to2} (x+ 2) \dfrac{1}{(x+2)(x-2)^2}

\implies  \lim \limits_{x \to2}  \dfrac{1}{(x-2)^2}

\implies \dfrac{1}{16}

\lim \limits_{x \to-2} (x+ 2)^2 q(x) =  \lim \limits_{x \to2} (x+ 2)^2 \dfrac{7}{(x+2)^2(x-2)^2}

\implies  \lim \limits_{x \to2}  \dfrac{7}{(x-2)^2}

\implies \dfrac{7}{16}

Hence, one (1) of them is non-analytical at x = 2.

Thus, x = 2 is an irregular singular point.

5 0
3 years ago
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