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sammy [17]
3 years ago
8

Which of the following gases will escape through a hole in a balloon at the highest rate? Kr NO Ar N2O

Chemistry
1 answer:
densk [106]3 years ago
4 0

Answer:

NO.

Explanation:

The rate of diffusion of gases is inversely proportional to the square root of its density as explained by Graham's law of diffusion i.e

Rate (R) & 1/√(density (d))

R & 1/√d

But the density of a gas is proportional to the molar mass (M) of the gas.

Thus, the above equation can written as:

R & 1/√d

R & 1/√M

This implies that rate is inversely proportional to the molar mass of a gas i.e the lighter the gas, the faster the rate and the heavier the gas, the slower the rate of diffusion.

Now, to obtain the answer to the question, let us determine the molar mass of each gas.

This is illustrated below:

Molar mass of Kr = 84 g/mol

Molar mass of NO = 14 + 16 = 30 g/mol

Molar mass of Ar = 40 g/mol

Molar mass of N2O = (14x2) + 16 = 44 g/mol

Summary

Gas >>>>>>> Molar mass

Kr >>>>>>>>> 84 g/mol

NO >>>>>>>> 30 g/mol

Ar >>>>>>>>> 40 g/mol

N2O >>>>>>> 44 g/mol

From the above table, we can see the lightest gas is NO.

Therefore, NO will escape through the hole in the balloon at the highest rate.

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yaroslaw [1]

Answer:

The answer to your question is below

Explanation:

Covalent bonds are bonds between to atoms that share a pair of electrons, there are three kinds of covalent bonds but I'll describe only two:

Covalent non polar bond: is a covalent bond between two elements of the same element. Ex two hydrogens, two chlorine, two oxygenes, etc.

Covalent polar bond: is a covalent bond between 2 elements of different elements, for example: hydrogen and chlorine or nitrogen, they are polar because on of the element that form it is smaller than the other one, then a partial positive and a partial negative charge is formed.

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3 years ago
Which statement is true about the exothermic reaction?
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Answer:

C

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Explanation:

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4 0
3 years ago
"how many molecules of carbon dioxide exit your lungs when you exhale 5.00 × 10−2 mol of carbon dioxide, co2?"
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We are going to use Avogadro's constant to calculate how many molecules of

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when 1 mole of CO2 has 6.02 x 10^23 molecules, so how many molecules in

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number of molecules = moles of CO2 * Avogadro's number

                                     = 5 x 10^-2  * 6.02 x 10^23

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∴ There are 3 x 10^22 molecules in CO2 exist in lungs 
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