Using the quadratic formula to solve x2 = 5 - x, what are the values of x?

Mathematics

1 answer:

RideAnS [48]3 years ago

8 0

Exact Form:

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Evaluate the line integral, where c is the given curve. c y3 ds,

postnew [5]

Parameterizing $\mathcal C$ by

$\mathbf r(t)=(t^3,t)$

with $0\le t\le2$ , we have

$\mathrm ds=\|\mathbf r'(t)\|\,\mathrm dt=\sqrt{(3t^2)^2+1^2}\,\mathrm dt=\sqrt{9t^4+1}\,\mathrm dt$

So

$\displaystyle\int_{\mathcal C}y^3\,\mathrm ds=\int_{t=0}^{t=2}t^3\sqrt{9t^4+1}\,\mathrm dt$
$=\displaystyle\frac1{36}\int_0^236t^3\sqrt{9t^4+1}\,\mathrm dt$
$=\displaystyle\frac1{36}\int_{u=1}^{u=145}\sqrt u\,\mathrm du$
$=\dfrac{145^{3/2}-1}{54}$

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3 years ago

Solve. 8 – 3x – x = 12 <br> x =?

poizon [28]

You have to isolate x. First you start off by adding the like terms which is -3x and -x. By adding them you get -4x.

8 - 4x = 12

Then you subtract 8 on both sides since it is positive to isolate x.
-4x = 4

Then you divide -4 by both sides and get x=4/-4

4/-4 is simplified to -1 so the answer is x= -1

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3 years ago

An inference _______.

Alex Ar [27]

Answer:

It is a possible explanation of events using prior knowledge

Step-by-step explanation:

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3 years ago

Whats the value of y help please

Aliun [14]

Answer:

Step-by-step explanation:

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3 years ago

Simplify<br> 6x^3y^9/36x^3y^-2

AnnZ [28]

6x^3y^9/36x^3y^-2 The x^3 values cancel each other out leaving the 1/6
(1/6)y^9/(y^-2) the y^-2 causes the y^9 to turn into y^11 (9+2=11)
(1/6)y^11/1 the 1/6 is multiplied by y^11
y^11/6

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2 years ago