3 years ago

What are the coordinates of the vertex of the function y=-1/16(x-3)^2+2

Mathematics

1 answer:

Masteriza [31]3 years ago

7 0

Answer:

(3,2)

Step-by-step explanation:

if you graph the function y=-1/16(x-3)^2+2

the vertex of this function will be (3,2)

ps.if its right can you mark me brainliest please???

thank you!!!!

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