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3 years ago

Which of the following is a chemical property of aluminum?

Chemistry

1 answer:

mestny [16]3 years ago

7 0

B. The boiling point of aluminum is 2519 degrees Celsius.

This is a chemical property of aluminum.

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What are 7 elements from the periodic table that are named after objects in outer space?

Alik [6]

Elements named after celestial bodies are the following. 1.Element 34 (Selenium) is named after the moon. Selene is Greek for moon 2. Element 2 (Helium) is named after the sun. Helios is Greek for sun. 3. Element 52 (Tellurium) is named after the earth. Tellus is the Latin word for earth. 4. Element 80 (Mercury) is named after the planet Mercury. The name Mercury is also a name of a Roman god. 5. Element 92 (Uranium) is named after the planet Uranus. 6. Element 93 (Neptunium) is named after the planet Neptune. 7. Element 94 (Plutonium) is named after the planet Pluto.

8 0

3 years ago

Compounds like CCl₂F₂ are known as chlorofluorocarbons, or CFCs. These compounds were once widely used as refrigerants but are n

Nataliya [291]

Explanation:

The given data is as follows.

Specific heat of water = $4.18 J/g^{o}C$

Heat of fusion of water = 334 J/g

Mass of water = 200 g

On bringing water at $0^{o}C$ , heat released will be as follows.

$q_{1} = m \times C \times \Delta T$

= $200 g \times 4.18 J/g^{o}C \times (0 - 15)^{o}C$

= -12540 J

or, = -12.540 kJ (as 1 kJ = 1000 J)

Now, calculate the heat releasedwhen water freezes at $0^{o}C$ as follows.

$q_{2} = mass \times \text{-heat of fusion}$

= $200 g \times -334 J/g$

= -66800 J

or, = -66.80 kJ

Therefore, total heat released in freezing water will be as follows.

$q_{total} = q_{1} + q_{2}$

= (-12.540 - 66.80) kJ

= -79.34 kJ

Hence,

amount of heat released in freezing water = heat used to vaporize $CCl_{2}F_{2}$

Now, heat of vaporization of $CCl_{2}F_{2}$ = 289 J/g

Total heat released in freezing water = -79.34 kJ

Heat consumed to vaporize $CCl_{2}F_{2}$ = 79.34 kJ = -79340 J

Therefore, calculate the mass of $CCl_{2}F_{2}$ vaporized as follows.

Mass of $CCl_{2}F_{2}$ vaporized = $\frac{\text{heat consumed}}{\text{heat of vaporization}}$

= $\frac{79340 J}{289 J/g}$

= 274.53 g

Thus, we can conclude that 274.53 g mass of this substance must evaporate to freeze 200 g of water initially at $15^{o}C$ .

5 0

4 years ago

How much copper is present in a cube that measures 3.20cm on each side, if the density of copper is 8.96 g/mL

Ainat [17]

Answer:

290.32 g

Explanation:

First we calculate the volume of the cube:

Volume = (3.20 cm)³ = 32.768 cm³

Now we convert cubic centimeters to mililiters:

32.768 cm³ * 1 mL / 1 cm³ = 32.768 mL

Finally we calculate the mass, using the equation for density:

Density = mass / Volume

mass = Density * Volume

mass = 8.86 g/mL * 32.768 mL = 290.32 g

7 0

3 years ago

There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. In

tatyana61 [14]

Answer:

-470.4 kJ/mol

Explanation:

Balanced reactions equations are as follows.

CaC2 (s) + 2H2O (l) â C2H2 (g) + CaOH2 (s) ÎH=â414.kJ

6C2H2 (g) + 3CO2 (g) + 4H2O (g) â 5CH2CHCO2H (g) ÎH=132.kJ

To get the 6 C2H2 we need to multiply first equation by 6

Then we get

6CaC2 (s) + 12H2O (l) â 6C2H2 (g) + 6CaOH2 (s) ÎH=â414.kJ * 6 = -2484 kJ

6C2H2 (g) + 3CO2 (g) + 4H2O (g) â 5CH2CHCO2H (g) ÎH=132.kJ

So the total energy produced = -2484 kJ + 132.0 kJ = -2352 kJ

This amount of energy is given out for the 5 moles of acid

So lets convert it for 1 mol

-2352 kJ * 1 mol / 5 mol = -470.4 kJ/mol

So the delta H of reaction for the formation of the acrylic acid is -470.4 kJ/mol

5 0

3 years ago

PLEASE HELP ASAPPPP

Liono4ka [1.6K]

So what you do is you write out each element separately and how many of that element on either side of the arrow S-8|S-1
O-2|O-2
on one side theres 8 (S) and 2 (O) and 1(S) and 2(O) if you put a number in front to balance it you are multiplying it the elements number like
SO2 if I put a 2 in front now I will have 2(S) and 4(O)

Answer is 1,8,8

8 0

4 years ago