The answer is 10 grams.
The atomic weights for each elements are :
<span>Na - 22.99 g/mol </span>
<span>O - 16.00 g/mol </span>
<span>H - 1.01 g/mol
The sum = 40 g/mol for NAOH
</span><span>0.250 moles * 40.00 g / 1 mole = 10 g NaOH</span>
3Na2O(at) + 2Al(NO3)3(aq) —> 6NaNO3(aq) + Al2O3(s)
This is a double replacement reaction and NaNO3 is aqueous because Na is an alkali metal, plus nitrate is in the solution. Both of these are soluble. Al2O3 is not soluble because it does not contain any element that is soluble and is hence the precipitate.
Hope this helped!
68 kg. There are 58 kg salt in 500 gal seawater.
<em>Step 1.</em> Convert gallons to litres
1 US gal = 3.79 L (1 Imp gal = 4.55 L)
<em>Step 2</em>. Find the volume of the seawater
Volume = 500 gal × (3.79 L/1 gal) = 1895 L
<em>Step 3</em>. Find the mass of the seawater
Mass = 1895 L × (1.025 kg/1 L) = 1942 kg
<em>Step 4</em>. Find the mass of the salt
Mass of salt = 1942 kg seawater × (3.5 kg salt/100 kg seawater) = 68 kg salt
The acceleration of the car : 2.5 m/s²
<h3>Further explanation</h3>
Newton's 2nd law explains that the acceleration produced by the resultant force on an object is proportional and in line with the resultant force and inversely proportional to the mass of the object
∑F = m. a
<h3 />
Mass of the car = 1200 kg
Forward force = 3400 N
Friction force = 400 N
The direction of motion of the friction force will be opposite to the forward force, so that both of them can be subtracted to get the value of the net force (net force: combination / sum of all forces acting on an object)

So the acceleration :

Answer:
Al4C3 + 12H2O = 3CH4 + 4Al(OH)3
Explanation:
Not sure if any explanation is needed but always start with the most complex compound. In this case it is Al(OH)3. You can see that there is 4 Aluminiums on the other side so I would start by putting a 4 next to the Al(OH)3. This now gives me 12 Hydrogens and 12 Oxygens on the right side. I put a 3 next to the CH4 to balance the Carbons on the left side. This leaves me with 12 Oxygens and 24 Hydrogens on the right side. This ends up being perfect because I can put a 12 next to the H2O.