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Nezavi [6.7K]
3 years ago
6

When used in a shorthand electron configuration, the noble gas core [He] represents 1s^2 2s^2 2p^6.

Chemistry
2 answers:
Ugo [173]3 years ago
8 0
True; electron configuration for He is 1s^2, 2s^2, 2p^6
alex41 [277]3 years ago
7 0
I think this is false.  If I remember correctly the noble gas core [He] represents 1s².  For example using the short hand notation for Boron you would do
[He] 2s²2p¹.

Hope this helps.  Let me know if you have any further questions or need any clarification.
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3 years ago
A 1.24g sample of a hydrocarbon, when completely burned in an excess of O2 yields 4.04g Co2 and 1.24g H20. Draw plausible struct
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Answer:

Plausible structure has been given below

Explanation:

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4.04 g of CO_{2} = \frac{4.04}{44}moles CO_{2} = 0.0918 moles of CO_{2}

1 mol of CO_{2} contains 1 mol of C atom

So, 0.0918 moles of CO_{2} contains 0.0918 moles of C atom

1.24 g of H_{2}O = \frac{1.24}{18}moles H_{2}O = 0.0689 moles of H_{2}O

1 mol of H_{2}O  contain 2 moles of H atom

So, 0.0689 moles of H_{2}O contain (2\times 0.0689)moles of H_{2}O or 0.138 moles of H_{2}O

Moles of C : moles of H = 0.0918 : 0.138 = 2 : 3

Empirical formula of hydrocarbon is C_{2}H_{3}

So, molecular formula of one of it's analog is C_{4}H_{6}

Plausible structure of C_{4}H_{6} has been given below.

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Answer:

0.8078 Kg

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Let us assume volume = 1 m^3

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the fraction of mass of liquid at 25°C.

4 0
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