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S_A_V [24]
3 years ago
5

3. In an atomic model, what particles are found inside the nucleus of an atom?

Chemistry
1 answer:
sukhopar [10]3 years ago
4 0

Answer:

Neurons and Protons

Explanation:

The Electrons are outside of the nucleus, also known as the <em>Electron</em><em> </em><em>Cloud</em><em>.</em>

I hope this was what you were looking for, and as always, I am joyous to assist anyone at any time.

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What kinds of places may hold life ?
emmasim [6.3K]

The planets that could host liquid water and might have rocky ... Liquid water is a necessity for the kind of life we know

7 0
3 years ago
A group of tissues that work together to perform a specific function is called
Phantasy [73]

Answer:

B. Organ.

Explanation:

College Biology Major here.

3 0
2 years ago
What is the name of the compound represented by the formula SI2BR6
yarga [219]

Answer:

Disilicon Hexabromide

Explanation:

A compound H2O is named – Dihydrogen monoxide. Its common name is of course water. A compound of Si2Br6 is named – Disilicon Hexabromide. 2.

6 0
3 years ago
At some temperature for the equilibrium PX3(g) + X2(g) # PX5(g) the equilibrium constant is 0.74. At the same temperature the eq
mariarad [96]

Answer: The equilibrium constant for PX_5(g)\rightarrow PX_3(g)+X_2(g) is 1.35

Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_c  

For the given chemical reaction:

PX_3(g)+X_2(g)\rightarrow PX_5(g)

The expression for K_c is written as:

K_c=\frac{[PX_5]^1}{[PX_3]^1[X_2]^1}

0.74=\frac{[PX_5]^1}{[PX_3]^1[X_2]^1}

For the reverse chemical reaction:

PX_5(g)\rightarrow PX_3(g)+X_2(g)

The expression for K_c' is written as:

K_c'=\frac{[PX_3]^1[X_2]^1}{[PX_5]^1}

K_c'=\frac{1}{K_c}=\frac{1}{0.74}=1.35

The equilibrium constant for PX_5(g)\rightarrow PX_3(g)+X_2(g) is 1.35

4 0
3 years ago
Calcular el valor de la presión osmótica que corresponde a una solución que contiene 2 moles de soluto en un litro de solución a
Brums [2.3K]

El valor de la presión osmótica que corresponde a una solución que contiene 2 moles de soluto en un litro de solución a una temperatura de 17°C es 47.56 atmósferas.

La presión osmótica se puede calcular usando la siguiente ecuación:

\pi = \frac{nRT}{V}   (1)

En donde:

n: es el número de moles = 2 moles

R: es la constante de los gases = 0.082 L*atm/(K*mol)

T: es la temperatura = 17 °C = 290 K

V: es el volumen = 1 L

Introduciendo lo valores anteriores en la ecuación (1), tenemos:

\pi = \frac{nRT}{V} = \frac{2 moles*0.082 L*atm/(K*mol)*290 K}{1 L} = 47.56 atm

Por lo tanto, la presión osmótica es 47.56 atmósferas.

Puedes encontrar más aca:

  • brainly.com/question/5041899?referrer=searchResults
  • brainly.com/question/5925156?referrer=searchResults

Espero que te sea de utilidad!

5 0
2 years ago
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