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2 years ago

How to measure the volume of a substance in a test tube?

1 answer:

6 0

Hello!
Answer:
Calculate Density Using Volume of a Cylinder.
That is one great way to measure the volume!
Hoping this helps you! ;D

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What is the maximum number of electrons found in any energy level of the known elements? (Refer to the periodic table.) 112 32 8

Makovka662 [10]

The answer is 32 electrons.

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2 years ago

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The equilibrium of 2H 2 O(g) 2H 2 (g) + O 2 (g) at 2,000 K has a Keq value of 5.31 x 10-10. What is the Keq expression for this

maks197457 [2]

Answer is: Keq expression for this system is Keq = [O₂ ] · [H₂]² ÷ [H₂O]².
Chemical reaction: 2H₂O(g) ⇄ O₂(g) + 2H₂(g).
The equilibrium constant (Keq) is a ratio of the concentration of the products (in this reaction oxygen and hydrogen) to the concentration of the reactants (in this reaction water).

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3 years ago

Please someone answer and help :)

algol [13]

13. D
14. A
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16. B
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2 years ago

Explain the formation of coke?

solniwko [45]

Answer:

Here is it....

Explanation:

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3 years ago

The balanced equation for combustion in an acetylene torch is shown below: 2C2H2 + 5O2 → 4CO2 + 2H2O The acetylene tank contains

andriy [413]

Answer: 67.2 moles

Explanation: $2C_2H5+5O_2\rightarrow 4CO_2+2H_2O$

According to the given balanced equation, 2 moles of acetylene $C_2H_2$ combine with 5 moles of oxygen $O_2$ to produce 4 moles of carbon dioxide $CO_2$ .

Thus if 2 moles of acetylene $C_2H_2$ combine with = 5 moles of oxygen $O_2$

35 moles of acetylene $C_2H_2$ combine with= $\frac{5}{2}\times {35}=87.5$ moles of oxygen $O_2$

But as only 84 moles of oxygen are available, acetylene is not a limiting reagent.

5 moles of oxygen $O_2$ reacts with = 2 moles of acetylene $C_2H_2$

84 moles of oxygen $O_2$ reacts with= $\frac{2}{5}\times {84}=33.6$ moles of acetylene $C_2H_2$

Thus Oxygen is the limiting reagent as it limits the formation of products. Acetylene is excess reagent as it is present in excess.

2 moles of acetylene $C_2H_2$ produce= 4 moles of carbon dioxide $CO_2$ .

33.6 moles of acetylene $C_2H_2$ produce= $\frac{4}{2}\times {33.6}=67.2$ moles of of carbon dioxide $CO_2$ .

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3 years ago

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