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vitfil [10]
3 years ago
14

How to measure the volume of a substance in a test tube?

Chemistry
1 answer:
Naya [18.7K]3 years ago
6 0
Hello!
Answer:
<span>Calculate Density Using Volume of a Cylinder.
That is one great way to measure the volume!
Hoping this helps you! ;D</span>
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A solid precipitate is formed from the reaction of lead nitrate and sodium chromate. What would be the best method to separate t
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Which of the following correctly identifies two of the eight elements of weather
Shtirlitz [24]
Are there any options?

8 0
3 years ago
When an atom of oxygen (O) forms an anion by gaining two electrons, what is the anion’s charge?
Rudiy27

Answer:

bdndbdjdbdjdbdjdbsidbdidbsjsbsisbsidbd

7 0
3 years ago
What mass in grams would 5.7L of hydrogen gas occupy at STP?​
tekilochka [14]

Answer:  The correct answer is:  " 0.54 g " .

__________________________________________

Explanation:

Note that "hydrogen gas" is:  

H₂ (g)  ;   that is:  a "diatomic element" (diatomic gas) ;

_________________________________________

The molecular weight of "H" is:  1.00794 g ;

   (From the Periodic Table of Elements).

So, the molecular weight of:  H₂ (g)  is:

    " 1.00794 g * 2  = 2.01588 g ; {use calculator) ;

_________________________________________

Note the conversion for a gas at STP:

______

  1 mol of a gas = 22.4 L gas;

___

i.e. " 1 mol / 22.4 L " ;

____

So:     " 5.7 L H₂ (g)  *  \frac{1 mol H_{2} }{22.4 L} *\frac{2.01588 g}{mol} =? ;

The "L" ("literes" cancel out to "1" ;  since "L/L = 1 ;

The "mol" (moles) cancel out to "1" ; since "mol/mol = 1 ;

____

and we are left with:

____

 [5.7 * 2.104588 g ] / 22.4  =  ?  g ;

______________________

→ [ 11.9961516  g ] / 22.4 =

          0.53554248214  g ;l

_____________________________

We round this value to:  " 0.54 g " ;

 → since "5.7 L " has 2 (two) significant figures;  

     22.4 is an exact number conversion;

     and "5.7 L" has fewer significant figures than:

    " 2.104588 " ; or:  " 1.00794 " .

  → as such: We round to "2 (two) significant figures."

______________________________

Hope this is helpful.  Wishing you the best in your academic endeavors!

_______________________________

8 0
3 years ago
What effect would the incomplete drying of a sample (for example, the incomplete removal of a re-crystallization solvent) on per
Varvara68 [4.7K]

Answer:

It will lead to overestimation of the percent recovery

Explanation:

The percent recovery refers to the percentage of the pure compound recovered after a chemical process. It is a ratio of the pure compound recovered to the original substance multiplied by 100%.

If the sample was incompletely dried and the recrystallization solvent is still present, the percent recovery will be overestimated and we will have a value that is greater than the accurate percent recovery due to solvent impurities present.

5 0
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