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GREYUIT [131]
3 years ago
6

-10-|1+4b|=-19 Y = 0

Mathematics
1 answer:
alexandr402 [8]3 years ago
3 0

Answer:

b=2 or b=-2.5

Step-by-step explanation:

We solve absolute value equations the same as any other equation using inverse operations. However, the inverse operation for absolute value requires one special condition. Since absolute values change a number to a positive regardless if it has a negative sign, we have two possible answers. When we have the absolute value operation isolated, we will set it equal to both the negative and positive option.  

-10-|1+4b|=-19\\-10+10-|1+4b|=-19+10\\-|1+4b|=-9\\\frac{-|1+4b|}{-1} =\frac{-9}{-1} \\|1+4b|=9

We now have the absolute value isolated. We will set it equal to both 9 and -9.

1+4b=9\\1-1+4b=9-1\\4b=8\\b=2

and

1+4b=-9\\1-1+4b=-9-1\\4b=-10\\b=\frac{-10}{4}=\frac{-5}{2}=  -2.5

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diamong [38]
1. Convert the mixed numbers into improper numbers (-3 2/5 = -17/5 and 8 1/5 = 41/5). Then add 17/5 to both sides when means b=58/5

2. Multiply both sides by the reciprocal of -7/3 (which is -3/7). So n=18
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Simplify x^3 y^3 / x^3 y^3
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\frac{1}{y}

Step-by-step explanation:

When simplifying an exponent a way to do is to expand the exponent. This means that it will now be

\frac{x*x*x*y*y*y}{x*x*x*y*y}

Whenever you see an x or y on the numerator and denominator cross it out because it is the same thing as 1

When you cross out all of the x's and y's the only variable left is y in the denominator. This means that the answer is \frac{1}{y}

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3 years ago
What is an equation of the line that passes through the point (-4,-6)(−4,−6) and is perpendicular to the line 2x-y=62x−y=6?
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3 years ago
Which statements are true about the graph of the function f(x) = x2 – 8x + 5? Check all that apply.
statuscvo [17]

Answer:

A, D, E are true

Step-by-step explanation:

You have to complete the square to prove A.  Do this by first setting the function equal to 0, then moving the 5 to the other side.

x^2-8x=-5

Now we can complete the square.  Take half the linear term, square it, and add it to both sides.  Our linear term is 8 (from the -8x).  Half of 8 is 4, and 4 squared is 16.  So we add 16 to both sides.

(x^2-8x+16)=-5+16

We will do the addition on the right, no big deal.  On the left, however, what we have done in the process of completing the square is to create a perfect square binomial, which gives us the h coordinate of the vertex.  We will rewrite with that perfect square on the left and the addition done on the right,

(x-4)^2=11

Now we will move the 11 back over, which gives us the k coordinate of the vertex.

(x-4)^2-11=y

From this you can see that A is correct.

Also we can see that the vertex of this parabola is (4, -11), which is why B is NOT correct.

The axis of symmetry is also found in the h value.  This is, by definition, a positive x-squared parabola (opens upwards), so its axis of symmetry will be an "x = " equation.  In the case of this type of parabola, that "x = " will always be equal to the h value.  So the axis of symmetry is

x = 4, which is why C is NOT correct, either.

We can find the y-intercept of the function by going back to the standard form of the parabola (NOT the vertex form we found by completing the square) and sub in a 0 for x.  When we do that, and then solve for y, we find that when x = 0, y = 5.  So the y-intercept is (0, 5).

From this you can see that D is also correct.

To determine if the parabola has real solutions (meaning it will go through the x-axis twice), you can plug it into the quadratic formula to find these values of x.  I just plugged the formula into my graphing calculator and graphed it to see that it did, indeed, go through the x-axis twice.  Just so you know, the values of x where the function go through are (.6833752, 0) and (7.3166248, 0).  That's why you need the quadratic formula to find these values.

7 0
3 years ago
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