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blagie [28]
3 years ago
13

A large western state consists of 2691 million acres of land. Approximately 65% of this pand is federally owned how to find the

answer?
Mathematics
1 answer:
PIT_PIT [208]3 years ago
7 0

Answer:

Step-by-step explanation:

What you need to do is take your 65% and put it over 100% like this: 65/100

Then, you take 2691 and put it into the denominator and put x on the top like this: x/2691

Then you need to put them equal to each other and cross multiply like this 65/100=x/2691

Multiply the 2691 by 65 and x by 100

to get 100x=2691(65)

Finally, multiply the 2691 by 65 and then divide that whole thing by 100 to get x.

x will be the land in acres and your final answer.

Good luck! Hope this was clear!

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finlep [7]

Answer:

it is becuse you do 13-4 which would give you nine.

6 0
3 years ago
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Find an explicit rule for the nth term of a geometric sequence where the second and fifth terms are -6 and 162, respectively.
Step2247 [10]
Hello,

a(2)=-6
a(3)=-6*r
a(4)=-6*r²
a(5)=-6*r^3=162
a(5)/a(2)=r^3=162/(-6)=-27==>r=-3

a(1)=-6/(-3)=2
a(2)=2*(-3)
a(3)=2*(-3)²
a(4)=2*(-3)^3
a(5)=2*(-3)^4

a(n)=2*(-3)^(n-1)




Answer
5 0
3 years ago
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A group consists of 6 men and 5 women. Five people are selected to attend a conference. In how many ways can 5 people be selecte
cluponka [151]

Answer:

462

6

1.2%

Step-by-step explanation:

Since the questions are combinations, we must apply the combination formula, which is as follows:

n C r = (n!) / (r! (n-r)!)

Because there are 6 men and 5 women, there are a total of 11 people.

Thus:

n = 11

In the first question in how many ways can 5 people be selected from this group of 11, r = 5.

Replacing in the formula:

11 C 5 = (11!) / (5! * (11-5)!)

11 C 5 = (11!) / (5! * 6!)

11 C 5 = 462

In the second question, in how many ways can 5 men be selected from the 6 men, here n = 6 and r = 5, replacing we are left with:

6 C 5 = (6!) / (5! * (6-5)!)

6 C 5 = (6!) / (5! * 1!)

6 C 5 = 6

In the last question of what is the probability that the selected group is all men, we have that it is the combination of the two previous questions. Since the total would be part A it would be the total of the combinations of choosing 5 of 11 people and part B of the 6 men that there are the combinations of choosing 5.

Divide the two values ​​from parts A and B to get ...

(result from part B) / (result from part A) = (# of ways to pick 5 men) / (# of ways to pick 5 people)

(result from part B) / (result from part A) = 6/462

(result from part B) / (result from part A) = 0.012

In other words, the probability is 1.2%

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3 years ago
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Answer:

y = 2x - 9

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y2 - y1 / x2 - x1

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I’m pretty sure the answer is C
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