Question

If someone can please help me out with my math, I would greatly appreciate it.

Answer 1

Answer:

The number of tickets they need to sell is $n=\frac{p}{(d-c)}$

Step-by-step explanation:

The formula is p = n(d - c), where

• P is the total profit made from the event
• n is the number tickets sold
• d is the price charged for each dinner
• c is the cost of food per plate

To find the number of tickets they need to sell separate n in one side and the other variables p, d and c in the other side

p = n(d - c)

n is multiplied by the difference of d and c, so lets divide both sides by the difference of d and c

$\frac{p}{(d-c)}=\frac{n(d-c)}{(d-c)}$

Cancel (D_C) up with (d - c) down in the right hand side

$\frac{p}{(d-c)}=n$

Switch the two side

$n=\frac{p}{(d-c)}$

The number of tickets they need to sell is $n=\frac{p}{(d-c)}$