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2 years ago

How much did one drop of HNO3 cause the pH of water to change?

Chemistry

2 answers:

Scrat [10]2 years ago

7 0

Answer:

-4

Explanation:

It went from a 7 to a 2 and 7-2 is 4, so it changed by 4 and it went down by 4.

ankoles [38]2 years ago

6 0

Assuming that there is missing information in this question I’m just going to go ahead and say that it’s lower.

HNO3 (nitric acid) is a very strong acid which should be found on the lower end of the pH scale. While water, on the other hand, is neutral and found at a pH of 7.

So if you add one drop of a strong acid into a neutral solution of 100ml let’s say, one can assume that the pH of that solution is now very low and probably found between 1-3 on a pH scale.

Reminder:

-Acids are found between 1-6 on the pH scale. The lower the number the stronger the acid

-Bases are found between 8-14 on the pH scale. The higher the number the stronger the base

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Temka [501]

Answer:

Respiration

Explanation:

The act of breathing, simple as that!

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2 years ago

Convert 25 liters per hour to milliliters per second.

Dominik [7]

Answer:

6.94444

Explanation:

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3 years ago

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Which event would be impossible to explain by using John Dalton’s model of the atom?

geniusboy [140]

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4 years ago

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1. A gas having the following composition is burnt under a boiler with 50% excess air.

jeka94

The composition of the stack gas are :

$CH_4$ = 0.8713

$C_3H_8$ = 0.0202

CO = 0.107

<h3 /><h3>What is a mole fraction?</h3>

The ratio of the number of moles of one component of a solution or other mixture to the total number of moles representing all of the components.

Assuming 100 g of the stack gas. Calculate the mass of each species in this sample according to their percentages.

Mass of $CH_4$ : 70% of 100 g = 70 g

Mass of $C_3H_8$ : 15% of 100 g = 15 g

Mass of CO : 15% of 100 g = 15 g

Now calculate the number of moles of each species:

Number of moles of $CH_4$ : $\frac{70 g}{16.04 g/mol}$ = 4.3 mole

Number of moles of $C_3H_8$ : $\frac{15 g}{144.1 g/mol}$ = 0.10 mole

Mass of CO : $\frac{15 g}{28.01 g/mol}$ = 0.53 mole

Now to calculate the mole fraction of each we use the formula:

Mole fraction of $CH_4$ : $\frac{4.3}{4.935}$ = 0.8713

Mole fraction of $C_3H_8$ : $\frac{0.10}{4.935}$ = 0.0202

Mole fraction of CO : $\frac{0.53}{4.935}$ = 0.107

Hence, composition of the stack gas are:

$CH_4$ = 0.8713

$C_3H_8$ = 0.0202

CO = 0.107

Learn more about mole fraction here:

brainly.com/question/13135950

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8 0

2 years ago

If 10.62 mL of a standard 0.3330 M KOH solution reacts with 98.20 mL of CH3COOH solution, what is the molarity of the acid solut

Nikolay [14]

Answer:

0.036 M of $CH_{3} COOH$

Explanation:

It is an example of acid-base neutralization reaction.

KOH + $CH_{3} COOH$ ----> $CH_{3} COO^{-} K^{+}$ + $H_{2}O$

Base Acid Salt

When two component react then the number of moles of both the component should be same, therefore the number of moles and acids and bases should be the same in the following .

Molarity= $\frac{\textrm{No. of Moles}}{\textrm{Volume of the Particular Solution}}$