Answer:
Type of hybridisation
Explanation:
For example , saturated hydrocarbons have sp3 hybridisation while unsaturated hydrocarbons have either sp2 or sp hybridisation.
Example: Ethane( C2H6) has sp3 hybridisation and ethene(C2H4) has sp2 hybridisation and Ethyne(C2H2) has sp hybridization.
Answer:
characteristic properties of an element are the defining properties of that element and it does not change with quantity of the element used.
Explanation:
the amount or the quantity of the element used does not affect the characteristic property of the element. it does not matter is the if the amount or the quantity of the element used in the reaction is large or the small the characteristic properties like boiling point, melting point, density, thermal conductivity, etc remain the same or remain constant.
This freezing point business is usually based on molality, that is moles solute per kilogram of solvent.
<span>molality = freezing point depression over Kf </span>
<span>In this case molality -10.3 degrees over -1.85 degrees Kf = 5.53 molal </span>
<span>This 5.53 molal solution is made up of l000 gms water and 5.53 moles glucose at 180 grams per mole for a total mass of 1997 grams </span>
<span>It volume would be l997 gms over 1.50 gms/ml or 1331 ml </span>
<span>We know that we have 5.53 moles of glucose dissolved in l331 ml of solution so now we can find how many moles of glucose in l000 ml or one liter of solution and this will be our Molarity </span>
<span>5.53 moles glucose over l331 ml = X moles glucose over l000 ml solution </span>
<span>cross multiply and solve for X moles glucose per liter solution </span>
<span>X = 4.15 moles glucose per liter = 4.15 Molar</span>
1) Calculate the number of moles of Cu SO4 . 5H20 by dividing the specified mass by the molar mass.
2) The ratio of production given by the equation is 1 mol of Cu SO4 . 5 H2O to 1 mol of Cu SO4=> 1:1, meaning that the number of moles of Cu SO4 produced is the same number of moles of Cu SO4.5H20 heated.
3) Finally mutiply the number of moles of Cu SO4 by its molar mass and there you have the mass of Cu SO4 produced.
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