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topjm [15]
3 years ago
9

When it is burned, 1 gallon of gasoline produces 1.3Ã108j of energy. 1500 kg car accelerates from rest to 37 m/s in 10 s. the en

gine of this car is only 15% efficient (which is typical), meaning that only 15% of the energy from the combustion of the gasoline is used to accelerate the car. the rest goes into things like the internal kinetic energy of the engine parts as well as heating of the exhaust air and engine.\?
Physics
1 answer:
andreev551 [17]3 years ago
3 0
Im sorry I dont knoow this
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Pls reply... plss!! help me​
viktelen [127]

Answer:

this is your solution

Explanation:

Answer-1 Iodine

Answer-2 Uterus

Answer-3 Adam's Apple

Answer-4 Distance

Answer-5 Carbon dioxide

Answer-6 Zygote

7 0
2 years ago
A 4.0-kg object is supported by an aluminum wire of length 2.0 m and diameter 2.0 mm. How much will the wire stretch?
forsale [732]

Answer:

The extension of the wire is 0.362 mm.

Explanation:

Given;

mass of the object, m = 4.0 kg

length of the aluminum wire, L = 2.0 m

diameter of the wire, d = 2.0 mm

radius of the wire, r = d/2 = 1.0 mm = 0.001 m

The area of the wire is given by;

A = πr²

A = π(0.001)² = 3.142 x 10⁻⁶ m²

The downward force of the object on the wire is given by;

F = mg

F = 4 x 9.8 = 39.2 N

The Young's modulus of aluminum is given by;

Y = \frac{stress}{strain}\\\\Y = \frac{F/A}{e/L}\\\\Y = \frac{FL}{Ae} \\\\e = \frac{FL}{AY}

Where;

Young's modulus of elasticity of aluminum = 69 x 10⁹ N/m²

e = \frac{FL}{AY} \\\\e = \frac{(39.2)(2)}{(3.142*10^{-6})(69*10^9)} \\\\e = 0.000362 \ m\\\\e = 0.362 \ mm

Therefore, the extension of the wire is 0.362 mm.

8 0
2 years ago
How do I answer this question
maria [59]

Answer:

what question

Explanation:

6 0
3 years ago
Read 2 more answers
Betty (mass 40 kg), standing on slippery ice, catches her leaping dog (mass 15 kg) moving horizontally at 3.0 m/s. Show that the
MA_775_DIABLO [31]

Answer:

v = 2.18m/s

Explanation:

In order to calculate the speed of Betty and her dog you take into account the law of momentum conservation. The total momentum before Betty catches her dog must be equal to the total momentum after.

Then you have:

Mv_{1o}+mv_{2o}=(M+m)v        (1)

M: mass Betty = 40kg

m: mass of the dog = 15kg

v1o: initial speed of Betty = 3.0m/s

v2o: initial speed of the dog = 0 m/s

v: speed of both Betty and her dog = ?

You solve the equation (1) for v:

v=\frac{Mv_{1o}+mv_{2o}}{M+m}=\frac{(40kg)(3.0m/s)+(15kg)(0m/s)}{40kg+15kg}\\\\v=2.18m/s

The speed fo both Betty and her dog is 2.18m/s

7 0
2 years ago
Which statement correctly compares and contrasts the information represented by the chemical formula and model of a compound?
Alina [70]
Models show how the atoms in a compound are connected.
6 0
3 years ago
Read 2 more answers
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