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Lesechka [4]
3 years ago
10

Helpppppp pleaseeeeeee

Mathematics
2 answers:
Allisa [31]3 years ago
8 0

Answer:

88 Inches^2

Step-by-step explanation:

Find the areas of one of the triangles and one of the rectangles, add them together, then multiply by 2.

scZoUnD [109]3 years ago
6 0

it's pretty simple if you look at it! :)

answer : 112

( 4 x 8 + 4 x 8 ) + ( 3 x 8 + 3 x 8 ) = 112

i think

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12 - C = –16<br> solve for C
inna [77]

Answer:

28

Step-by-step explanation:

1) subtract 12 from both sides

2) divide by negative 1

3 0
3 years ago
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A gardener uses 144 feet of fencing to build a rectangular garden. The function A(w)=24w−w2 can be used to find the area of the
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Answer:

The graph of the equation is shown in the picture attached below.

We can see w = 12 corresponds to the global maximum of the function, and for any w greater than 12 the value of A(w) decreases.

This means that for any value of the width greater than 12, the function cannot model the situation.

Making the equation only valid for

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3 years ago
The weight, w, of a spring in pounds is given by 0.9 times the square root of the energy, E, stored by the spring in joules. If
alex41 [277]

Answer:

B) w\approx3.12 pounds

Step-by-step explanation:

w=0.9\sqrt{E}

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6 0
2 years ago
How do you write 220% as a fraction or mixed number in simplest form?
Kay [80]
220% is 2.20 in decimal form in fraction 2 1/5
7 0
3 years ago
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Find the points on the ellipse 4x2 + y2 = 4 that are farthest away from the point (−1, 0).
Hitman42 [59]
<span>The two points that are most distant from (-1,0) are exactly (1/3, 4sqrt(2)/3) and (1/3, -4sqrt(2)/3) approximately (0.3333333, 1.885618) and (0.3333333, -1.885618) Rewriting to express Y as a function of X, we get 4x^2 + y^2 = 4 y^2 = 4 - 4x^2 y = +/- sqrt(4 - 4x^2) So that indicates that the range of values for X is -1 to 1. Also the range of values for Y is from -2 to 2. Additionally, the ellipse is centered upon the origin and is symmetrical to both the X and Y axis. So let's just look at the positive Y values and upon finding the maximum distance, simply reflect that point across the X axis. So y = sqrt(4-4x^2) distance is sqrt((x + 1)^2 + sqrt(4-4x^2)^2) =sqrt(x^2 + 2x + 1 + 4 - 4x^2) =sqrt(-3x^2 + 2x + 5) And to simplify things, the maximum distance will also have the maximum squared distance, so square the equation, giving -3x^2 + 2x + 5 Now the maximum will happen where the first derivative is equal to 0, so calculate the first derivative. d = -3x^2 + 2x + 5 d' = -6x + 2 And set d' to 0 and solve for x, so 0 = -6x + 2 -2 = -6x 1/3 = x So the furthest point will be where X = 1/3. Calculate those points using (1) above. y = +/- sqrt(4 - 4x^2) y = +/- sqrt(4 - 4(1/3)^2) y = +/- sqrt(4 - 4(1/9)) y = +/- sqrt(4 - 4/9) y = +/- sqrt(3 5/9) y = +/- sqrt(32)/sqrt(9) y = +/- 4sqrt(2)/3 y is approximately +/- 1.885618</span>
7 0
3 years ago
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