Answer:
2-naphtol is a weak acid and benzoic acid is a stronger acid. NaHCO3 is a weak base, that will only react with a strong acid like benzoic acid. 2-napthol is not soluble in sodium bicarbonate.
Explanation:
2-naphtol is a phenol. Phenol is made of a benzene attached to an OH group. So, it is a (big) organic molecule, and a little non-polar group. The conjugated (or non-localised) electrons in the benzene ring pull electrons away from the OH group. It makes it harder for the oxygen to steal the hydrogen's electrons and become O-.
A phenol is acidic in nature because of this H+ releasing. This will result in forming a phenoxide.
Benzoic acid is a carboxylic acid and is more acidic than a phenol. Since it's acid it will also release H+ ion, in this case to form carboxylate which is more stable than phenoxide. The phenoxide is resonance stabilised.
The negative charge , in carboxylate, is delecoalised on the negatively charged O atom what makes it more stable than phenoxide. Compared to carboxylic acid. ( or benzoic acid) phenol ( or 2-naphtol) is a weak acid.
NaHCO3 is a weak base and will only react with a strong acid like carboxylic acid. A naphtol is not strong enough to react with the weak base NaHCO3.
This means 2-naphtol is a weak acid and benzoic acid is a stronger acid. NaHCO3 is a weak base, that will only react with a strong acid like benzoic acid. 2-napthol is not soluble in sodium bicarbonate.
<span>Hexane is nonpolar, so you would not see dipole-dipole, hydrogen-bonding, or ion-dipole interactions involving it. London dispersion forces always exist however, and the ion-ion force between Na+ and Cl- will still exist since it's not dependent on the environment. So 2 and 5 would be check-marked.</span>
Answer:
Explanation:
If the reaction is really exothermic (and it is) then the water would spatter all over the place. It would boil off if the container could hold it. It would also react according to the following reaction.
You are talking about a reaction like
2K + 2HOH = 2KOH + H2
1.7 M..............................