A homogeneous mixture is a mixture whose parts are the same throughout.
Answer:
A) 15.5 mL
Explanation:
Given, Mass of oxalic acid = 0.3500 g
Molar mass of oxalic acid = 90.03 g/mol
The formula for the calculation of moles is shown below:
Thus,
According to the given reaction:
5 moles of oxalic acid react with 2 moles of potassium permanganate
Thus,
1 mole of oxalic acid react with 2/5 moles of potassium permanganate
0.0038876 mole of oxalic acid react with 
moles of potassium permanganate
Moles of potassium permanganate = 0.001555 moles
Also, considering:
Molarity = 0.100 M
So,
Volume = 0.01555 L
Also, 1 L = 1000 mL
So, volume = 15.5 mL
Answer:
1.02 g is the theoretical yield for PbCO₃
Explanation:
The reaction is
Pb(CH₃COO)₂ + CO₂ + H₂O → PbCO₃ + 2CH₃COOH
1 mol of lead(II) acetate react with 1 mol of carbon dioxide and 1 mol of water toproduce 1 mol of lead(II) carbonate and 2 moles of acetic acid.
With the two mass of the reactants, let's find put the limiting reactant.
1.25 g / 325.29 g/mol = 3.84×10⁻³ moles
5.95 g / 44 g/mol = 0.135 moles
Certainly, the limiting reactant is the lead(II) acetate. Ratio is 1:1, so if I have 0.135 moles of dioxide, I need the same amount of acetate. I only have 3.84×10⁻³ moles, that's why this is the limiting reactant.
Ratio is 1:1 too, with the lead(II) carbonate so 3.84×10⁻³ moles of acetate would produce 3.84×10⁻³ moles of carbonate.
Let's convert the moles to mass:
3.84×10⁻³ mol . 267.2 g/ mol = 1.02 g
Answer:
A handful (130 grams) of sodium azide will produce 67 liters of nitrogen gas--which is enough to inflate a normal air bag. 0.03 SECOND is all it takes to inflate an air bag.
Based on the balanced equation reactants to product ratio are 2:3 for Azide: Nitrogen gas. This means for every 3 moles of Nitrogen gas produces, 2 moles of Sodium Azide are needed
Explanation:
PH + pOH = 14
pH + 8 = 14
pH= 6
