How does a balanced chemical equation demonstrate the Law of Conservation of Mass?

Describe the attraction between 2 atoms as a result of sharing electrons

torisob [31]

A chemical bond is an attraction between atoms that allows the formation of chemical substances that contain two or more atoms. The bond is caused by the electrostatic force of attraction between opposite charges, either between electrons and nuclei, or as the result of a dipole attraction

6 0

3 years ago

What is the classification of clouds based on?

Rus_ich [418]

Cloud level (ft)Cloud type

High clouds (CH)

Base usually 20,000 ft or above, over British Isles

<span>CirrusCirrocumulusCirrostratus</span>

Medium clouds (CM)

Base usually between 6,500 and 20,000 ft over British Isles.

<span>AltocumulusAltostratusNimbostratus</span>

Low clouds (CL)

Base usually below 6,500 ft over British Isles.

hope this helps!

8 0

3 years ago

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Chlorine can be prepared in the laboratory by the reaction of manganese dioxide with hydrochloric acid, HCl(aq)HCl(aq) , as desc

LekaFEV [45]

Answer:

1.131g of MnO2

Explanation:

Step 1:

The balanced equation for the reaction.

MnO2(s) + 4HCl(aq)—> MnCl2(aq) + 2H2O(l) + Cl2(g)

Step 2:

Data obtained from the question. This includes:

Volume (V) of Cl2 = 295mL = 0.295L

Temperature (T) = 25°C = 25°C + 273 = 298K

Pressure (P) = 795 Torr = 795/760 = 1.05 atm

Number of mole (n) of Cl2 =.?

Gas constant (R) = 0.082atm.L/Kmol

Step 3:

Determination of the number of mole of Cl2 produced. The number of mole of Cl2 produced from the reaction can be obtained by applying the ideal gas equation as follow:

PV = nRT

1.05 x 0.295 = n x 0.082 x 298

Divide both side by 0.082 x 298

n = (1.05 x 0.295)/(0.082 x 298)

n = 0.013 mole.

Therefore, the number of mole of Cl2 produced is 0.013 mole.

Step 4:

Determination of number of mole of MnO2 needed to produce 0.013 mole of Cl2.

This is illustrated below:

From the balanced equation above,

1 mole of MnO2 produced 1 mole of Cl2.

Therefore, it will also take 0.013 mole of MnO2 to produce 0.013 mole of Cl2.

Step 5:

Converting 0.013 mole of MnO2 to grams. This is illustrated below:

Number of mole MnO2 = 0.013 mole

Molar Mass of MnO2 = 55 + (2x16) = 87g/mol

Mass of MnO2 =?

Mass = number of mole x molar Mass

Mass of MnO2 = 0.013 x 87

Mass of MnO2 = 1.131g

Therefore 1.131g of MnO2 should be added to excess HCl.

4 0

3 years ago

The following reactions are used in batteries:Reaction I is used in fuel cells, II in the automobile lead-acid battery, and III

elixir [45]

The highest ratio is -0.613kj/g which is for automobile lead-acid battery .

Given ,

Reaction-1 used in fuel cells

Reaction-2 used in automobile lead-acid battery

Reacttion-3 used in experimental high-temperature battery for powering electric vehicles .

1) Fuel cells :

2H2(g) + O2(g) ==> 2H20 (l) , E^0cell = 1.23V

We know ,

Free energy is the maximum work done .

delta G = Wmax

=> Wmax = delta G = -4.75*10^5j/mol e^- = -4.75*10^2 kj/ mol e^-

Molecular mass of 1 mole of H2 = 2 .016 g / mol e^-

Molecular mass of 2 mole of H2 = 4.032 g/mol e^-

Molecular mass of O2 = 32 g/mol e^-

Total mass of the reactants = (4.032+32)g/mol e^- = 36.032 g/mol e^-

Ratio of Wmax to the total mass of the reactants

=Wmax/ total mass of the reactants

=( -4.75*10^2 kj/mol e^-)/36.032 g/mol e^-

=-13.2kj/g

Therefore , the ratio of Wmax to total mass of the reactants is -13.2kj/g .

2) Automobile lead-acid battery :

Pb(s) + PbO2(s) + 2H2SO4(aq) ==> 2PbSO4 (s) + 2H2O (l) , E^0cell = 2.04V

We know ,

Wmax = delta G = -3.94*10^5j/mol e^- = -3.94*10^2kj/mol e^-

molecular mass of Pb = 207.2 g /mol e^-

molecular mass of Pbo2 = 239.2g/mol e^-

molecular mass of H2SO4 = 98.008g/mol e^-

molecular mass of 2 mole of H2SO4 = 196.016g/mol e^-

total mass of the reactants = (207.2+239.2+196.016)g/mol e^- = 642.416g/mol e^-

Ratio of Wmax to total mass of the reactants

= Wmax/total mass of reactants

=(-3.94*10^2kj/mol e^-)/642.416g/mol e^-

=-0.613kj/g

Hence ,the ratio of Wmax to the total mass of the reactants of automobile lead-acid battery is -0.613kj/g .

3) Experimental high temperature battery :

2Na(l) +FeCl2(s) ==> 2NaCl (s) + Fe(s) , E^0 cell = 2.35V

We know ,

Wmax = delta G = -4.53*10^5j/mol e^- = -4.53*10^2kj/mol e^-

molecular mass of Na = 22.99 g/mol e^-

molecular mass of 2 moles of Na = 45.98g/mol e^-

molecular mass of FeCl2 = 126.85 g/mol e^-

total mass of the reactants =( 45.98+ 126.85)g/mol e^- = 172.83 g/mol e^-

Ratio of Wmax to the total mass of the reactants

= Wmax / total mass of reactants

=(-4.53*10^2kj/mol e^-)/ 172.83g/mol e^-

=-2.62kj/g

Therefore , the ratio of Wmax to the total mass of the reactants in an experimental high temperature battery is -2.62kj/g .

Hence , the highest ratio is -0.613kj/g which is of lead -acid battery .

Learn more about fuel cell here :

brainly.com/question/13603874

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4 0

2 years ago

The mc002-1.jpgHrxn of formation of carbon dioxide is negative. Which statement is true?

Ymorist [56]

What is true about the statement is that it is equal to the same root as the formation of the carbon

4 0

3 years ago