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Molodets [167]
3 years ago
14

Determine the number of moles of compound and the number of moles of each type of atom in each of the following:

Chemistry
1 answer:
den301095 [7]3 years ago
5 0

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

  • <u>For a:</u>

Mass of propylene = 25 g

Molar mass of propylene = 42 g/mol

Putting values in equation 1, we get:

\text{Moles of }C_3H_8=\frac{25g}{42g/mol}=0.6mol

In 1 mole of propylene, 3 moles of carbon atoms and 8 moles of hydrogen atoms are present.

So, in 0.6 moles of propylene, (3\times 0.6)=1.8mol of carbon atoms and (8\times 0.6)=4.8mol of hydrogen atoms are present.

Thus, the number of moles of compound is 0.6 moles and number of moles of carbon and hydrogen atoms are 1.8 moles and 4.8 moles respectively.

  • <u>For b:</u>

Mass of glycine = 3.06\times 10^{-3}g

Molar mass of glycine = 75 g/mol

Putting values in equation 1, we get:

\text{Moles of glycine}=\frac{3.06\times 10^{-3}g}{75g/mol}=4.08\times 10^{-5}mol

In 1 mole of glycine, 2 moles of carbon atoms, 5 moles of hydrogen atoms, 1 mole of nitrogen atom and 2 moles of oxygen atoms are present.

So, in 4.08\times 10^{-5}mol of glycine, (2\times 4.08\times 10^{-5})=8.16\times 10^{-5}mol of carbon atoms, (5\times 4.08\times 10^{-5})=2.04\times 10^{-4}mol of hydrogen atoms, (1\times 4.08\times 10^{-5})=4.08\times 10^{-5}mol of nitrogen atoms and (2\times 4.08\times 10^{-5})=8.16\times 10^{-5}mol of oxygen atoms are present.

Thus, the number of moles of compound is 4.08\times 10^{-5}mol moles and number of moles of carbon, hydrogen, nitrogen and oxygen atoms are 8.16\times 10^{-5}mol, 2.04\times 10^{-4}mol, 4.08\times 10^{-5}mol and 8.16\times 10^{-5}mol respectively.

  • <u>For c:</u>

Mass of Treflan = 25 lbs = 11350 g   (Conversion factor: 1 lbs = 454 g)

Molar mass of Treflan = 283.28 g/mol

Putting values in equation 1, we get:

\text{Moles of Treflan}=\frac{11350g}{283.28g/mol}=40mol

In 1 mole of treflan, 13 moles of carbon atoms, 16 moles of hydrogen atoms, 2 mole of nitrogen atom, 4 moles of oxygen atoms and 1 mole of fluorine are present.

So, in 40.03 moles of treflan, (13\times 40)=520mol of carbon atoms, (16\times 40)=640mol of hydrogen atoms, (2\times 40)=80mol of nitrogen atoms, (4\times 40)=160mol of oxygen atoms and (1\times 40)=40mol of fluorine atoms are present.

Thus, the number of moles of compound is 40 moles and number of moles of carbon, hydrogen, nitrogen, oxygen and fluorine atoms are 520 moles, 640 moles, 80 moles, 160 moles and 40 moles respectively.

  • <u>For d:</u>

Mass of Paris green = 0.125 kg = 125 g    (Conversion factor: 1 kg = 1000 g)

Molar mass of Paris green = 618.11 g/mol

Putting values in equation 1, we get:

\text{Moles of Paris green}=\frac{125g}{618.11g/mol}=0.202mol

In 1 mole of Paris green, 4 moles of carbon atoms, 6 moles of hydrogen atoms, 4 moles of copper atom, 10 moles of oxygen atoms and 2 moles of arsenic are present.

So, in 0.202 moles of Paris green, (4\times 0.202)=0.808mol of carbon atoms, (6\times 0.202)=1.212mol of hydrogen atoms, (4\times 0.202)=0.808mol of copper atoms, (10\times 0.202)=2.02mol of oxygen atoms and (2\times 0.202)=0.404mol of arsenic atoms are present.

Thus, the number of moles of compound is 0.202 moles and number of moles of carbon, hydrogen, copper, oxygen and arsenic atoms are 0.808 moles, 1.212 moles, 0.808 moles, 2.02 moles and 0.404 moles respectively.

  • <u>For e:</u>

Mass of Aspirin = 325 mg = 0.325 g    (Conversion factor: 1 g = 1000 mg)

Molar mass of aspirin = 180.16 g/mol

Putting values in equation 1, we get:

\text{Moles of aspirin}=\frac{0.325g}{180.16g/mol}=0.0018mol

In 1 mole of aspirin, 9 moles of carbon atoms, 8 moles of hydrogen atoms and 4 moles of oxygen atoms are present.

So, in 0.0018 moles of aspirin, (9\times 0.0018)=0.0162mol of carbon atoms, (8\times 0.0018)=0.0144mol of hydrogen atoms and (4\times 0.0018)=0.0072mol of oxygen atoms are present.

Thus, the number of moles of compound is 0.0018 moles and number of moles of carbon, hydrogen and oxygen are 0.0162 moles, 0.0144 moles and 0.0072 moles respectively.

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How many mol of phosphorus are obtained if 74.85 mol of carbon is used​
mixer [17]

Answer:

34.73

Explanation:

6 0
3 years ago
What’s the answer????
dezoksy [38]
Should be , b
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8 0
2 years ago
Consider the reaction 2 S + 3 O2 → 2 SO3 , which has a 75.1% yield. How much O2 is consumed if 583 g of SO3 are produced?
Ymorist [56]

Answer:

A/1.      10.9 mol O2

Explanation:

583 g x 1 mol SO3 x 3 mol O2 /

      80.057 g mol SO3 x 2 mol SO3

- You just need to find molar mass of SO3, which is 80.057 g.

- Everything else came from formula. Further explanation...

- Always start with what they give, such as 583 g. Then find 1 mol of what is being produced, in this it is SO3. We already found this because we did molar mass above. Next. find how many moles of what they want, which is O2. Look in equation and you can see 3 mol in from of O2. Next, do the same for SO3 and you can find 3 mol in front of that. Lastly, just do the math.

- If you need a further explanation or more help on any problems I would be happy to help, just let me know.

4 0
3 years ago
A sample of an unknown metal has a mass of 58.932g. it has been heated to 101.00 degrees C, then dropped quickly into 45.20 mL o
yaroslaw [1]
<h3>Answer:</h3>

0.111 J/g°C

<h3>Explanation:</h3>

We are given;

  • Mass of the unknown metal sample as 58.932 g
  • Initial temperature of the metal sample as 101°C
  • Final temperature of metal is 23.68 °C
  • Volume of pure water = 45.2 mL

But, density of pure water = 1 g/mL

  • Therefore; mass of pure water is 45.2 g
  • Initial temperature of water = 21°C
  • Final temperature of water is 23.68 °C
  • Specific heat capacity of water = 4.184 J/g°C

We are required to determine the specific heat of the metal;

<h3>Step 1: Calculate the amount of heat gained by pure water</h3>

Q = m × c × ΔT

For water, ΔT = 23.68 °C - 21° C

                       = 2.68 °C

Thus;

Q = 45.2 g × 4.184 J/g°C × 2.68°C

    = 506.833 Joules

<h3>Step 2: Heat released by the unknown metal sample</h3>

We know that, Q =  m × c × ΔT

For the unknown metal, ΔT = 101° C - 23.68 °C

                                              = 77.32°C

Assuming the specific heat capacity of the unknown metal is c

Then;

Q = 58.932 g × c × 77.32°C

   = 4556.62c Joules

<h3>Step 3: Calculate the specific heat capacity of the unknown metal sample</h3>
  • We know that, the heat released by the unknown metal sample is equal to the heat gained by the water.
  • Therefore;

4556.62c Joules = 506.833 Joules

c = 506.833 ÷4556.62

  = 0.111 J/g°C

Thus, the specific heat capacity of the unknown metal is 0.111 J/g°C

8 0
3 years ago
Sum of brother and sisters age is 26. Four times the brothers age is subtracted from three times the sisters age, the difference
lana66690 [7]

Answer : The ages of the brother and sister are, 10 and 16 years respectively.

Solution :

Let the age of brother be 'x' and the age of sister be 'y'

There are two equations formed which are,

x + y = 26      ..........(1)

3y - 4x = 8     ..........(2)

First we have to multiple equation (1) by 4 and then added equation (1) and (2), we get the value of 'y'.

4x+4y+3y-4x=8+26\\\\7y=112\\\\y=16

Now put the value of 'y' in equation (2), we get the value of 'x'

3(16) - 4x = 8

4x = 40

x = 10

The age of brother = x = 10 years

The age of sister = y = 16 years

Therefore, the ages of the brother and sister are, 10 and 16 years respectively.

3 0
3 years ago
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