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2 years ago

What is the mean of 31, 29, 33, 37, 33, 38, 43 and 40?

Mathematics

1 answer:

horsena [70]2 years ago

6 0

Answer: 35.5

Step-by-step explanation: The mean of a data set is equal to the sum of the set of numbers divided by how many numbers are in the set.

So to find the mean of the data set shown here, let's begin by adding the numbers.

31 + 29 + 33 + 37 + 33 + 38 + 43 + 40 = 284

284 will be divided by how many numbers are in the data set which is 8 so we have to divide 284 by 8.

248 ÷ 8 = 35.5

Therefore, the mean of the data set shown here is 35.5.

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3 years ago

If the probability of a student taking a calculus class is 0.10, the probability of taking a statistics class is 0.90, and the p

Stells [14]

Answer:

93% probability of a student taking a calculus class or a statistics class

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student takes a calculus class.

B is the probability that a student takes a statistics class.

We have that:

$A = a + (A \cap B)$

In which a is the probability that a student takes calculus but not statistics and $A \cap B$ is the probability that a student takes both these classes.

By the same logic, we have that:

$B = b + (A \cap B)$

The probability of taking a calculus class and a statistics class is 0.07

This means that $A \cap B = 0.07$

The probability of taking a statistics class is 0.90

This means that $B = 0.9$ . So

$B = b + (A \cap B)$

$0.9 = b + 0.07$

$b = 0.83$

The probability of a student taking a calculus class is 0.10

This means that $A = 0.1$

$A = a + (A \cap B)$

$0.1 = a + 0.07$

$a = 0.03$

What is the probability of a student taking a calculus class or a statistics class

$A \cup B = a + b + A \cap B = 0.03 + 0.83 + 0.07 = 0.93$

93% probability of a student taking a calculus class or a statistics class

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3 years ago