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3 years ago

9

Developers work together with customers and useras to define requirements and specify what the proposed system will do. If once

it is built, the system works according to specification but harms someone physicall or financially, who is responsible?

Computers and Technology

1 answer:

yarga [219]3 years ago

7 0

Financially would be responsible

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100 points, PLEASE HELP...To generate numbers between and including -10 to 10 you would use:

Orlov [11]

Answer:

A number line?

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2 years ago

In mathematics, the notation n! represents the factorial of the nonnegative integer n. The factorial of n is the product of all

hram777 [196]

Answer:

The program to this question can be given as:

Program:

factorial=1 #declare a variable.

number=int(input("Enter a positive integer:")) #input a number.

while (number>0): #loop

factorial= factorial*number # holding value in factorial variable

number=number-1

print('=',factorial) #print value.

Output:

Enter a positive integer:6

= 720

Explanation:

The description of the above python program can be given as:

In the above program firstly we define a variable that is "factorial". In this variable, we assign a value that is 1 and it is used to calculate the factorial value.
We define a variable "number". The number variable is used to take input from the user.
Then we define a loop in the loop we calculate the factorial and hold the value in the factorial value in the last we print the value.

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2 years ago

a cryptarithm is a mathematical puzzle where the goal is to find the correspondence between letters and digits such that the giv

Leokris [45]

Using the knowledge in computational language in C++ it is possible to write a code that cryptarithm is a mathematical puzzle where the goal is to find the correspondence between letters and digits

<h3>Writting the code:</h3>

<em>#include <bits/stdc++.h></em>

<em>using namespace std;</em>

<em>// chracter to digit mapping, and the inverse</em>

<em>// (if you want better performance: use array instead of unordered_map)</em>

<em>unordered_map<char, int> c2i;</em>

<em>unordered_map<int, char> i2c;</em>

<em>int ans = 0;</em>

<em>// limit: length of result</em>

<em>int limit = 0;</em>

<em>// digit: index of digit in a word, widx: index of a word in word list, sum: summation of all word[digit] </em>

<em>bool helper(vector<string>& words, string& result, int digit, int widx, int sum) { </em>

<em> if (digit == limit) {</em>

<em> ans += (sum == 0);</em>

<em> return sum == 0;</em>

<em> }</em>

<em> // if summation at digit position complete, validate it with result[digit].</em>

<em> if (widx == words.size()) {</em>

<em> if (c2i.count(result[digit]) == 0 && i2c.count(sum%10) == 0) {</em>

<em> if (sum%10 == 0 && digit+1 == limit) // Avoid leading zero in result</em>

<em> return false;</em>

<em> c2i[result[digit]] = sum % 10;</em>

<em> i2c[sum%10] = result[digit];</em>

<em> bool tmp = helper(words, result, digit+1, 0, sum/10);</em>

<em> c2i.erase(result[digit]);</em>

<em> i2c.erase(sum%10);</em>

<em> ans += tmp;</em>

<em> return tmp;</em>

<em> } else if (c2i.count(result[digit]) && c2i[result[digit]] == sum % 10){</em>

<em> if (digit + 1 == limit && 0 == c2i[result[digit]]) {</em>

<em> return false;</em>

<em> }</em>

<em> return helper(words, result, digit+1, 0, sum/10);</em>

<em> } else {</em>

<em> return false;</em>

<em> }</em>

<em> }</em>

<em> // if word[widx] length less than digit, ignore and go to next word</em>

<em> if (digit >= words[widx].length()) {</em>

<em> return helper(words, result, digit, widx+1, sum);</em>

<em> }</em>

<em> // if word[widx][digit] already mapped to a value</em>

<em> if (c2i.count(words[widx][digit])) {</em>

<em> if (digit+1 == words[widx].length() && words[widx].length() > 1 && c2i[words[widx][digit]] == 0) </em>

<em> return false;</em>

<em> return helper(words, result, digit, widx+1, sum+c2i[words[widx][digit]]);</em>

<em> }</em>

<em> // if word[widx][digit] not mapped to a value yet</em>

<em> for (int i = 0; i < 10; i++) {</em>

<em> if (digit+1 == words[widx].length() && i == 0 && words[widx].length() > 1) continue;</em>

<em> if (i2c.count(i)) continue;</em>

<em> c2i[words[widx][digit]] = i;</em>

<em> i2c[i] = words[widx][digit];</em>

<em> bool tmp = helper(words, result, digit, widx+1, sum+i);</em>

<em> c2i.erase(words[widx][digit]);</em>

<em> i2c.erase(i);</em>

<em> }</em>

<em> return false;</em>

<em>}</em>

<em>void isSolvable(vector<string>& words, string result) {</em>

<em> limit = result.length();</em>

<em> for (auto &w: words) </em>

<em> if (w.length() > limit) </em>

<em> return;</em>

<em> for (auto&w:words) </em>

<em> reverse(w.begin(), w.end());</em>

<em> reverse(result.begin(), result.end());</em>

<em> int aa = helper(words, result, 0, 0, 0);</em>

<em>}</em>

<em />

<em>int main()</em>

<em>{</em>

<em> ans = 0;</em>

<em> vector<string> words={"GREEN" , "BLUE"} ;</em>

<em> string result = "BLACK";</em>

<em> isSolvable(words, result);</em>

<em> cout << ans << "\n";</em>

<em> return 0;</em>

<em>}</em>

See more about C++ code at brainly.com/question/19705654

#SPJ1

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1 year ago

Which of the following is not one of the four methods for classifying the various instances of malware by using the primary trai

BlackZzzverrR [31]

Answer: Source

Explanation: The malware is the software persisting malicious approach to cause the damage/loss.The primary trait of the malware are infection,concealment,etc.

The concealment refer to the malware such as the Trojan horse, and other viruses that has only purpose to cause the malfunctioning in the system.The virus that get into the other software and then damage the system in known as the infectious malware .

The circulation is the transferring of the virus in the circular manner between the system for the damaging.Thus,the only trait that is not the part of the malware is source.

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3 years ago

How many bytes make up the word panthers

Sati [7]

It is saying 8 bytes

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3 years ago