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3 years ago

Positron Emission and electron capture are most different because they are.

Chemistry

1 answer:

snow_lady [41]3 years ago

6 0

Answer:

Opposites

Explanation:

In positron emission, a proton is converted to a neutron by emitting a positron and a neutrino. In electron capture, an outside electron is pulled inside the nucleus and combined with a proton to make a neutron, emitting only a neutrino.

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A 581.2 mL sample of carbon dioxide was heated to 347 K.

svetlana [45]

Answer:

The temperature at 581.2 mL volume was 242.8 K.

Explanation:

Using Charle's law

$\frac {V_1}{T_1}=\frac {V_2}{T_2}$

Given ,

V₁ = 581.2 mL

V₂ = 830.5 mL

T₁ = ?

T₂ = 347 K

Using above equation as:

$\frac {581.2\ mL}{T_1}=\frac {830.5\ mL}{347\ K}$

$T_1=\frac{581.2\times 347}{830.5}\ K=242.8\ K$

<u>The temperature at 581.2 mL volume was 242.8 K.</u>

3 0

4 years ago

"A nuclear reaction of significant historical note occurred in 1932, when a beryllium target was bombarded with alpha particles.

rodikova [14]

Answer: $_{0}^{1}\textrm{e}$ is missing

Explanation:

In a nuclear reaction, the total mass and total atomic number remains the same.

For the given reaction:

$^{4}_{2}\textrm{He}+^9_4\textrm{Be}\rightarrow ^{12}_{6}\textrm{C}+^A_Z\textrm{X}$

To calculate A:

Total mass on reactant side = total mass on product side

4 + 9 = 12 + A

A = 1

To calculate Z:

Total atomic number on reactant side = total atomic number on product side

2 + 4 = 6 + Z

Z = 0

$^{4}_{2}\textrm{He}+^9_4\textrm{Be}\rightarrow ^{12}_{6}\textrm{C}+^1_0\textrm{e}$

Hence, missing is $_{0}^{1}\textrm{e}$ .

8 0

3 years ago

Nitrogen dioxide and water react to form nitric acid and nitrogen monoxide, like this:

posledela

Answer: The value of the equilibrium constant Kc for this reaction is 3.72

Explanation:

Equilibrium concentration of $HNO_3$ = $\frac{15.5g}{63g/mol\times 9.5L}=0.026M$

Equilibrium concentration of $NO$ = $\frac{16.6g}{30g/mol\times 9.5L}=0.058M$

Equilibrium concentration of $NO_2$ = $\frac{22.5g}{46g/mol\times 9.5L}=0.051M$

Equilibrium concentration of $H_2O$ = $\frac{189.0g}{18g/mol\times 9.5L}=1.10M$

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as $K_c$