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Verizon [17]
3 years ago
12

Which is not on a station model? *

Chemistry
1 answer:
Fiesta28 [93]3 years ago
6 0
The answer is fronts
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Why is hydrogen (H) placed with the elements in Group 1A?
Alex787 [66]
It has ns1 electron configuration like the alkali metals. 
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3 years ago
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Eukaryotic gene expression is regulated during transcription and RNA processing, which take place in the nucleus, and during pro
Arlecino [84]

Answer:

Ok, is this a true and false question? Anyways, yes. the central dogma, from dna transcription to mRNA translation to proteins. and further regulation can occur through post-translational modifications of proteins. it is a true statement

Explanation:

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3 years ago
Nicotine, a component of tobacco, is composed of c, h, and n. a 4.725 −mg sample of nicotine was combusted, producing 12.818 mg
ehidna [41]

C = 12.818 mg CO2 (1 mmol CO2/44 mg CO2) (1 mmol C/1 mmol CO2) = 0.29 mmol

H = 3.675 mg of H2O (1 mmol H2O/18 mg H2O) (2 mmol H/1 mmol H2O) = 0.41 mmol

N = (4.725 mg – 0.29 * 12 – 0.41 * 1) * (1 mmol/14 mg) = 0.06 mmol

Divide everything by the smallest number:

C = 0.29/0.06 = 4.8 ~ 5

<span>H = 0.41/0.06 = 6.8 ~  7</span>

N = 0.06/0.06 = 1

 

Empirical formula is:

<span>C5H7N</span>

6 0
3 years ago
Determine the rate of a reaction that follows the rate law:
Natali5045456 [20]
A. 0.12 (mol/L)/s

rate = 1 x 10-2 • 2^2 • 3
8 0
3 years ago
The chemical equation below shows the burning of magnesium (Mg) with oxygen (O2) to form magnesium oxide (MgO). 2Mg + O2 Right a
Nadusha1986 [10]

Answer:

64.0

Explanation:

2Mg+O2 ---> 2MgO

use dimentional analysis to find the amount of moles of O2 needed first

4.00molMg x 1.00mol O2/ 2.00 mol Mg=. 2.00 mol O2

using the coefficients you can see the mole ratio for O2:Mg the mole ratio is 1:2 which is why there is 1 mole on the top for 2 moles on the bottom. The Mg would cancel and multiply 4 by 1 then divide by 2, or multipy 4 by 1/2

Now that you have the moles of O2 you use the molar mass to find the grams in 2 moles of O2

2.00 mol O2 x 32.0g/1.00 mol = 64.0 g

multiply 2 by 32

4 0
3 years ago
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