80% which would be 8/10 which would be 4/5 but honestly choose 3/4
Answer:
5.706x10⁻³M
Explanation:
Based on product solubility of Ca(OH)₂:
Ca(OH)₂(s) ⇆ Ca²⁺ + 2OH⁻(aq)
Ksp = 5.5x10⁻⁶ = [Ca²⁺] [OH⁻]²
<em>Where </em>[Ca²⁺] is 0.05M and [OH⁻] is obtained from the reaction with HCl.
The molar solubility, S, will be:
S = [OH⁻]/2
The [OH-] is:
<em>Moles HCl = Moles OH⁻</em>
2.77x10⁻³L * (0.103mol / L) = 2.85x10⁻⁴ moles OH⁻ in 25mL = 0.025L:
2.85x10⁻⁴ moles OH⁻ / 0.025L = 0.0114M = [OH⁻]
And S is:
0.0114M/2 =
<h3>5.706x10⁻³M</h3>
We know that molarity is equal to the moles of solute/liters of solution. In the problem, they tell us that there is 1 liter of solution, so we have to find how many moles of solute there are. Since they give us the amount of solute in grams, we can use the molar mass of CO₂ to find how many moles there are:
Carbon has a molar mass of 1<span>2.012 g/mol
</span>
Oxygen has a molar mass of 15.999 g/mol. Since there are 2 (which we can see from the subscript), we have to multiply this number by 2. (15.999)(2)=31.998 g/mol
We can find the total molar mass of CO₂ by adding these two numbers up:
12.012+31.998=44.01 g/mol
We can then use dimensional analysis to find how many moles there are:
100 g CO₂ (1 mol CO₂/44.01 g CO₂)
=2.27 moles of CO₂
Now that we have the moles of solute and liters of solution, we can plug them into our molarity equation:
<u>M</u>= 2.27 moles/ 1 liter
<u>M</u>= 2.27 moles/liter
Answer:
x = 2+
Explanation:
1) FADH2 + Q => FAD + QH2
Since H is added to Q
=> Reactant reduced is Q
(2) Balancing charges on both sides of the equation gives:
QH2 + 2 cyt c(Fe3+) => Q + 2 cyt c(Fe2+) + 2 H+
Thus x = 2+