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8090 [49]
3 years ago
9

Which element experiences greater London dispersion forces

Chemistry
1 answer:
natali 33 [55]3 years ago
8 0
Its d its the only one that makes sense


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Strontium metal reacts with aluminum chlorate to produce strontium
Fudgin [204]

Answer: single replacement reaction, 3Sr+2Al(ClO_3)_3\rightarrow 3Sr(ClO_3)_2+2Al

Explanation:

A single replacement reaction is one in which a more reactive element displaces a less reactive element from its salt solution.

A general single displacement reaction can be represented as :

XY+Z\rightarrow XZ+Y

As strontium metal is added to aluminum chlorate , strontium being more reactive than aluminium, displaces aluminium atom its salt solution and lead to formation of strontium  chlorate and aluminum metal.

3Sr+2Al(ClO_3)_3\rightarrow 3Sr(ClO_3)_2+2Al

3 0
3 years ago
Antimony has two naturally occuring isotopes, Sb121 and Sb123, Sb121 has an atomic mass of 120. 9038 u , and sb123 has an atomic
tino4ka555 [31]

Answer:

nah i dont feel like it

Explanation:

4 0
3 years ago
How is the potential (voltage) of a redox reaction determined using the reduction
LuckyWell [14K]

Answer:

caused by the ability of electrons to flow from one half cell too the other

Explanation:

How is the potential voltage of a redox reaction?

The potential difference is caused by the ability of electrons to flow from one half cell to the other. Electrons are able to move between electrodes because the chemical reaction is a redox reaction. A redox reaction occurs when a certain substance is oxidized, while another is reduced.

6 0
3 years ago
How many grams of PbBr2 will precipitate when excess CuBr2 solution is added to 77.0 mL of 0.595 M Pb(NO3)2 solution?Pb(NO3)2(aq
Alexxx [7]

Answer:

16.89g of PbBr2

Explanation:

First, let us calculate the number of mole of Pb(NO3)2. This is illustrated below:

Molarity of Pb(NO3)2 = 0.595M

Volume = 77mL = 77/1000 = 0.077L

Mole =?

Molarity = mole/Volume

Mole = Molarity x Volume

Mole of Pb(NO3)2 = 0.595x0.077

Mole of Pb(NO3)2 = 0.046mol

Convert 0.046mol of Pb(NO3)2 to grams as shown below:

Molar Mass of Pb(NO3)2 =

207 + 2[ 14 + (16x3)]

= 207 + 2[14 + 48]

= 207 + 2[62] = 207 +124 = 331g/mol

Mass of Pb(NO3)2 = number of mole x molar Mass = 0.046 x 331 = 15.23g

Molar Mass of PbBr2 = 207 + (2x80) = 207 + 160 = 367g/mol

Equation for the reaction is given below:

Pb(NO3)2 + CuBr2 —> PbBr2 + Cu(NO3)2

From the equation above,

331g of Pb(NO3)2 precipitated 367g of PbBr2

Therefore, 15.23g of Pb(NO3)2 will precipitate = (15.23x367)/331 = 16.89g of PbBr2

8 0
3 years ago
Reactants are substances that?
RSB [31]
A substance that undergoes change during a reaction, usually from coming in contact with another substance
4 0
3 years ago
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